Let events
A=Nathan has allergy
~A=Nathan does not have allergy
T=Nathan tests positive
~T=Nathan does not test positive
We are given
P(A)=0.75 [ probability that Nathan is allergic ]
P(T|A)=0.98 [probability of testing positive given Nathan is allergic to Penicillin]
We want to calculate probability that Nathan is allergic AND tests positive
P(T n A)
From definition of conditional probability,
P(T|A)=P(T n A)/P(A)
substitute known values,
0.98 = P(T n A) / 0.75
solving for P(T n A)
P(T n A) = 0.75*0.98 = 0.735
Answer:
EF = 1.5. DF = 2.
Step-by-step explanation:
DE is half of AB so EF is half of BC and DF is half of AC.
Answer:
$4.59
Step-by-step explanation:
20 - 1.20 - 5.03 = 13.77
13.77/3 = 4.59
The numbers are 18 and 12
