All categories

2 years ago

Solve for W -5.1=1.3+w/4

1 answer:

7 0

-5.1=1.3+w/4
Subtract 1.3 from both sides
-6.4=w/4
Multiply both sides by 4
-25.6=w

Check work:
-5.1=1.3+(-25.6/4)
-5.1=1.3+(-6.4)
-5.1=1.3-6.4
-5.1=-5.1

Hope this helps! :)

You might be interested in

To make lemonade, 2 cups of lemon juice are mixed with 7 cups of water.Describe and correct the error in proportion used to find

kumpel [21]

x/9 = 8/36 
x = 9 * 8/36 [multiplying each side by 9] 
x = 2 
 
x/90 = 4.4/12 
x = 90 * 4.4/12 [multiplying each side by 90] 
x = 33 

Both proportions should be expressed as lemon juice to water, or water to lemon juice. Either way would give a correct answer: 
2/7 = j/28 [lemon juice to water] 
8 = j [multiplying each side by 28] 

7/2 = 28/j [water to lemon juice] 
7j = 56 [multiplying each side by 2j] 
j = 8 [dividing each side by 7] 

The length proportion is 24 in to 32 ft. 
The actual house is 24 ft tall. 
Let x represent the doll house height, in inches. Then 
x/24 = 24/32 
x = 24 * 24/32 = 18 inches

3 0

3 years ago

Answer quickly! It very urgent

ra1l [238]

Answer: Because the graphs of the two equations overlap each other

Step-by-step explanation:

Every point on the first line also satisfies the second equation.

This is the same as equivalent fractions

where 1/2 = 2/4 = 3/6 = 4/8

Graphing these on a number line would only show one dot.

6 0

2 years ago

5/9*18/25 i need help

Akimi4 [234]

Answer:

$\frac{2}{5}$

Step-by-step explanation:

$\frac{5}{9} * \frac{18}{25} = \frac{5 * 18}{9 * 25} = \frac{90}{225} = \frac{45 * 2}{45 * 5} = \frac{2}{5}$

4 0

3 years ago

1. Write the form of the partial fraction decomposition of the rational expression. Do not solve for the constants.

german

Answer:

Step-by-step explanation:

To write the form of the partial fraction decomposition of the rational expression:

We have:

$\mathbf{\dfrac{8x-4}{x(x^2+1)^2}= \dfrac{A}{x}+\dfrac{Bx+C}{x^2+1}+\dfrac{Dx+E}{(x^2+1)^2}}$

Using partial fraction decomposition to find the definite integral of:

$\dfrac{2x^3-16x^2-39x+20}{x^2-8x-20}dx$

By using the long division method; we have:

$x^2-8x-20 | \dfrac{2x}{2x^3-16x^2-39x+20 }$

$- 2x^3 -16x^2-40x$

$x+ 20$

So;

$\dfrac{2x^3-16x^2-39x+20}{x^2-8x-20}= 2x+\dfrac{x+20}{x^2-8x-20}$

By using partial fraction decomposition:

$\dfrac{x+20}{(x-10)(x+2)}= \dfrac{A}{x-10}+\dfrac{B}{x+2}$

$= \dfrac{A(x+2)+B(x-10)}{(x-10)(x+2)}$

x + 20 = A(x + 2) + B(x - 10)

x + 20 = (A + B)x + (2A - 10B)

Now; we have to relate like terms on both sides; we have:

A + B = 1 ; 2A - 10 B = 20

By solvong the expressions above; we have:

$A = \dfrac{5}{2}$ $B = \dfrac{3}{2}$

Now;

$\dfrac{x+20}{(x-10)(x+2)} = \dfrac{5}{2(x-10)} + \dfrac{3}{2(x+2)}$

Thus;

$\dfrac{2x^3-16x^2-39x+20}{x^2-8x-20}= 2x + \dfrac{5}{2(x-10)}+ \dfrac{3}{2(x+2)}$

Now; the integral is:

$\int \dfrac{2x^3-16x^2-39x+20}{x^2-8x-20} \ dx = \int \begin {bmatrix} 2x + \dfrac{5}{2(x-10)}+ \dfrac{3}{2(x+2)} \end {bmatrix} \ dx$

$\mathbf{\int \dfrac{2x^3-16x^2-39x+20}{x^2-8x-20} \ dx = x^2 + \dfrac{5}{2}In | x-10|\dfrac{3}{2} In |x+2|+C}$

3. Due to the fact that the maximum words this text box can contain are 5000 words, we decided to write the solution for question 3 and upload it in an image format.

Please check to the attached image below for the solution to question number 3.