The value of the population of the growth of an endangered birth after 5 years is 1975
<h3>How to determine the population after 5 years?</h3>
The population function is given as:
B(t) = 100 + 3/5t^5
At 5 years, the value of t is 5
So, we have
t = 5
Next, we substitute 5 for t in the equation B(t) = 100 + 3/5t^5
This gives
B(5) = 100 + 3/5 * 5^5
Evaluate the exponent
B(5) = 100 + 3/5 * 3125
Evaluate the product
B(5) = 100 + 1875
Evaluate the sum
B(5) = 1975
Hence, the value of the population of the growth of an endangered birth after 5 years is 1975
Read more about exponential functions at:
brainly.com/question/2456547
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Answer:
12150 ft^3
Step-by-step explanation:
= (45)(20)(10) + (350)(9)
= 9000 + 3150
= 12150 ft^3
A(b-c)=ab-ac
(1/7)(1/3h-1/2)=(1/7)(1/3h)-(1/7)(1/2)=1/21h-1/14
now we gots
6 and 1/7+1/21h-1/14
rearange
6 and 1/7-1/14+1/21h
make common denom which is 14
6 and 2/14-1/14+1/21h
6 and 1/14+1/21h
Answer:
-12
Step-by-step explanation:
6 ÷ -1/2
Copy dot flip
6 * -2/1
-12
