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3 years ago

Geometric Sequence Assistance

Mathematics

1 answer:

11Alexandr11 [23.1K]3 years ago

4 0

Sum(3+9+27+81+243)=363

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Help me this one out, pls?

Flura [38]

Answer:

∠ACD= 109°

Step-by-step explanation:

∠A=38

180- ∠A= ∠B+C

180-38= 2∠B( ∠B=∠C) ( angles opposite to equal sides are equal)

142=2∠B

∠B=71

∠ACD=∠A+∠B ( exterior angle property)

∠ACD= 38+ 71= 109°

4 0

3 years ago

1 Mrs. Castro has 100 spoon and 80 forks if she put them in buckets what is the biggest number of spoon or forks that bucket wil

Yuri [45]

Answer:

Step-by-step explanation:

Here, we want to get the biggest number of spoon or forks that the bucket will have

What we have to do here is to simply find the greatest common factor of 100 and 80

Finding the greatest common factor of both will

give the biggest number of spoon or forks that the bucket will have

Mathematically, the greatest common factor of 80 and 100 is 10

3 0

4 years ago

Factor completely<br> 125x-27x^4<br> Step by step explanation

Vera_Pavlovna [14]

Answer:

125x - 33x⁴

Pull out like factors :

125x - 27x⁴ = -x • (27x3 - 125)

Factoring: 27x³- 125

Theory : A difference of two perfect cubes, a³ - b³ can be factored into

(a-b) • (a² +ab +b²)

(a-b)•(a²+ab+b²) =

a³+a²b+ab²-ba²-b²a-b³ =

a³+(a2b-ba²)+(ab²-b²a)-b³ =

a³+0+0+b³ =

a³+b³

Check : 27 is the cube of 3

Check : 125 is the cube of 5

Check : x³ is the cube of x¹

Factorization is :

(3x - 5) • (9x² + 15x + 25)

8 0

4 years ago

What is 70% of 53? PLZZZ HELP ASAP

rusak2 [61]

53 times 70%
53 times 0.7 is 37.1

4 0

3 years ago

Solve equation by the quadratic formula. List the solutions, separated by commas.<br> 4r^2 +3r+10=8

slega [8]

Answer:

$-\frac{3}{8} +\frac{\sqrt[]{23}i }{8},-\frac{3}{8} -\frac{\sqrt[]{23}i }{8}$

$-0.375+0.599479i,-0.375-0.599479i$

Step-by-step explanation:

$4r^2+3r+10=8$

Bring the 8 to the left side so that we equal the equation to 0. To do this, simply substract 8 on both sides.

$4r^2+3r+10-8=8-8\\4r^2+3r+2=0$

Where;

$a=4\\b=3\\c=2$

$Formula: x=\frac{-b\frac{+}{}\sqrt[]{b^2-4ac} }{2a}$

Replace. Let x be r

$r=\frac{-3\frac{+}{}\sqrt[]{(3)^2-4(4)(2)} }{2(4)}$

$r=\frac{-3\frac{+}{}\sqrt[]{9-32} }{8}$

$r=\frac{-3\frac{+}{}\sqrt[]{-23} }{8}$

It has no real solution because the square root is negative.

We can say that,

$r=-\frac{3}{8} \frac{+}{}\frac{\sqrt[]{23}*\sqrt[]{-1} }{8}$

$r=-\frac{3}{8} \frac{+}{}\frac{\sqrt[]{23}i }{8}$

$r_1=-0.375+0.599479i\\r_2=-0.375-0.599479i$

5 0

3 years ago