1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Oksi-84 [34.3K]
3 years ago
8

Can someone please help me with this?

Mathematics
1 answer:
vovikov84 [41]3 years ago
6 0
Remember that X will always be one up or down depending on if there is a - or not (if it is just an x) and one over! Hope this helps

You might be interested in
Which of the following graphs shows the solution set for the inequality below? 3|x + 1| < 9
Bas_tet [7]

Step-by-step explanation:

The absolute value function is a well known piecewise function (a function defined by multiple subfunctions) that is described mathematically as

                                 f(x) \ = \ |x| \ = \ \left\{\left\begin{array}{ccc}x, \ \text{if} \ x \ \geq \ 0 \\ \\ -x, \ \text{if} \ x \ < \ 0\end{array}\right\}.

This definition of the absolute function can be explained geometrically to be similar to the straight line   \textbf{\textit{y}} \ = \ \textbf{\textit{x}}  , however, when the value of x is negative, the range of the function remains positive. In other words, the segment of the line  \textbf{\textit{y}} \ = \ \textbf{\textit{x}}  where \textbf{\textit{x}} \ < \ 0 (shown as the orange dotted line), the segment of the line is reflected across the <em>x</em>-axis.

First, we simplify the expression.

                                             3\left|x \ + \ 1 \right| \ < \ 9 \\ \\ \\\-\hspace{0.2cm} \left|x \ + \ 1 \right| \ < \ 3.

We, now, can simply visualise the straight line,  y \ = \ x \ + \ 1 , as a line having its y-intercept at the point  (0, \ 1) and its <em>x</em>-intercept at the point (-1, \ 0). Then, imagine that the segment of the line where x \ < \ 0 to be reflected along the <em>x</em>-axis, and you get the graph of the absolute function y \ = \ \left|x \ + \ 1 \right|.

Consider the inequality

                                                    \left|x \ + \ 1 \right| \ < \ 3,

this statement can actually be conceptualise as the question

            ``\text{For what \textbf{values of \textit{x}} will the absolute function \textbf{be less than 3}}".

Algebraically, we can solve this inequality by breaking the function into two different subfunctions (according to the definition above).

  • Case 1 (when x \ \geq \ 0)

                                                x \ + \ 1 \ < \ 3 \\ \\ \\ \-\hspace{0.9cm} x \ < \ 3 \ - \ 1 \\ \\ \\ \-\hspace{0.9cm} x \ < \ 2

  • Case 2 (when x \ < \ 0)

                                            -(x \ + \ 1) \ < \ 3 \\ \\ \\ \-\hspace{0.15cm} -x \ - \ 1 \ < \ 3 \\ \\ \\ \-\hspace{1cm} -x \ < \ 3 \ + \ 1 \\ \\ \\ \-\hspace{1cm} -x \ < \ 4 \\ \\ \\ \-\hspace{1.5cm} x \ > \ -4

           *remember to flip the inequality sign when multiplying or dividing by

            negative numbers on both sides of the statement.

Therefore, the values of <em>x</em> that satisfy this inequality lie within the interval

                                                     -4 \ < \ x \ < \ 2.

Similarly, on the real number line, the interval is shown below.

The use of open circles (as in the graph) indicates that the interval highlighted on the number line does not include its boundary value (-4 and 2) since the inequality is expressed as "less than", but not "less than or equal to". Contrastingly, close circles (circles that are coloured) show the inclusivity of the boundary values of the inequality.

3 0
2 years ago
HELP ASAP!!!!! i wasted 30 points because i asked this question 3 times with no answer please.​
Effectus [21]
Your slope of this graph is: 4/3x
7 0
3 years ago
You are asked to draw a triangle with side lengths of 3 inches, 4 inches, and 1 inch. How many triangles like this can you draw?
marishachu [46]
I think you can draw two of them.

As you walk around the triangle in the clockwise direction,
you can run into the sides in the order of

                 3  ==>  4  ==>  1

or in the order of

                 3  ==>  1  ==>  4 .

Those are mirror images of each other.  So they're not congruent,
and I think they're considered different triangles.

        
6 0
3 years ago
30.16=17.56+5x<br> What is the answer?
Thepotemich [5.8K]

Answer:

2.52= x

Step-by-step explanation:

3 0
3 years ago
Can someone please help meee
e-lub [12.9K]

Answer:

-10

Step-by-step explanation:

y2- y1 -7 -3

---------- ----------

x2 - x1 -6 6

3 0
2 years ago
Other questions:
  • Which number is composite?<br> 31<br> 43<br> 37<br> 49
    7·1 answer
  • Shirts with a school's mascot were printed, and the table shows the number of people who bought them the first, second, third, a
    8·1 answer
  • Which of the following would affect an employee’s net pay?
    5·2 answers
  • . Bob makes 4% commission on his sales as a real estate agent. If Bob sells a house for $249,000, how much money does he earn
    15·1 answer
  • andrea has a mystery number that is not on the hundreds chart. the product of the digits of her number is 36. her number is prim
    13·1 answer
  • Evaluate the expression when a= 1/4 and b= 6<br> 5b/32a2=?
    9·1 answer
  • Determine whether you can construct many, one, or no triangle(s) with each description.
    10·1 answer
  • PLEASE HELP I WILL GIVE A LOT OF POINTS!
    6·1 answer
  • Convert0.9285714 into a fraction
    14·1 answer
  • Given right triangle jkl, what is the value of cos(l)? five-thirteenths five-twelfths twelve-thirteenths twelve-fifths
    8·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!