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3 years ago

7.5 Cheetah Speed and reasoning

Mathematics

1 answer:

Anika [276]3 years ago

3 0

Answer: whats the queation

Step-by-step explanation:

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How do I solve this?

ladessa [460]

It would be
y=(-16*-1)
which would then be
y=16
so the answer would be
(-16,16)
you replace the x in the equation with the x you are given

3 0

4 years ago

Can someone help me on questions 10-15

Mazyrski [523]

Answer:

10. Supplementary

11. Congruent

12. Congruent.

13 . congruent

14 supplement

15 supplementary

<h3>Hope this helps you </h3><h3>Do mark as brainliest! </h3>

3 0

3 years ago

Convert 3<br> 8 into a decimal.

marishachu [46]

Answer:

0.375

Step-by-step explanation:

3/8=0.375, use a calculator for this or long division

7 0

3 years ago

abduls average speed is 40 mph in heavy traffic and his average speed is 50 mph in light traffic for 1 hour and light traffic fo

alexira [117]

Answer:

over 9000

^^^

Liar.

Step-by-step explanation:

over 9000

^^^

Liar.

3 0

3 years ago

Find [5(cos 330 degrees + I sin 330 degrees)]^3

earnstyle [38]

Given a complex number in the form:
$z= \rho [\cos \theta + i \sin \theta]$
The nth-power of this number, $z^n$ , can be calculated as follows:

- the modulus of $z^n$ is equal to the nth-power of the modulus of z, while the angle of $z^n$ is equal to n multiplied the angle of z, so:
$z^n = \rho^n [\cos n\theta + i \sin n\theta ]$
In our case, n=3, so $z^3$ is equal to
$z^3 = \rho^3 [\cos 3 \theta + i \sin 3 \theta ] = (5^3) [\cos (3 \cdot 330^{\circ}) + i \sin (3 \cdot 330^{\circ}) ]$ (1)
And since
$3 \cdot 330^{\circ} = 990^{\circ} = 2\pi +270^{\circ}$
and both sine and cosine are periodic in $2 \pi$ , (1) becomes
$z^3 = 125 [\cos 270^{\circ} + i \sin 270^{\circ} ]$

6 0

3 years ago