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pashok25 [27]
3 years ago
14

Find the distance between the point (-2,4) and (5,-1)

Mathematics
1 answer:
Sunny_sXe [5.5K]3 years ago
7 0
The answer is 8.36 hope this helps
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Point T(-9,5) lies on the perpendicular bisector of UV. If the
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The coordinate of point V is at (-16, 9)

If Point T(-9,5) lies on the perpendicular bisector of UV, this means that the point divides the line UV into two equal parts

Given the following coordinates

Midpoint T = (-9, 5)

U = (-2, 1)

Required

coordinate of point V

Using the midpoint formulas;

T(x, y) = (\frac{x_1+x_2}{2}, \frac{y_1+y_2}{2}) \\T(-9, 5) = (\frac{-2+x_2}{2}, \frac{1+y_2}{2})

Get the value if x₂ and y₂

-9 = \frac{-2+x_2}{2}\\-18 = -2+x_2\\x_2 = -18+2\\x_2 = -16\\

Similarly;

5 = \frac{1+y_2}{2}\\10 = 1+y_2\\y_2 = 10-1\\y_2 = 9\\

Hence the coordinate of point V is at (-16, 9)

Learn more here: brainly.com/question/18049211

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