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pashok25 [27]
3 years ago
14

Find the distance between the point (-2,4) and (5,-1)

Mathematics
1 answer:
Sunny_sXe [5.5K]3 years ago
7 0
The answer is 8.36 hope this helps
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Rewrite the fraction 29/50 with a denominator of 100
romanna [79]

Answer:

58/100

50 X 2 = 100

29 X 2 = 58

8 0
3 years ago
a point on a perpendicular bisector is 7cm from each endpoint of the bisected segment and 5cm from the point of intersection. Wh
love history [14]

9514 1404 393

Answer:

  about 9.80 cm

Step-by-step explanation:

The length of half the segment (h) can be found from the Pythagorean theorem:

  h² +5² = 7²

  h² = 7² -5² = 49 -25 = 24

  h = √24 = 2√6

This is half the segment length, so the whole segment length is ...

  L = 2h = 2(2√6)

  L = 4√6 ≈ 9.7980

The length of the segment is 4√6 ≈ 9.80 cm.

8 0
3 years ago
Which is the graph of y=2/(x+1)-6
krek1111 [17]

Answer:

I have linked the graph in an image

Step-by-step explanation:

1. Simplify  y=2/(x+1)-6

2. Subtract the numbers 1-6=-5

3. = 2/x-5

4. Graph your results

4 0
3 years ago
Read 2 more answers
Make a table with the domain of {2,3,4,5,6} and draw a graph of the absolute value function y = 2|x-4| + 3.
Jet001 [13]

Answer:

<h2>In the attachment.</h2>

Step-by-step explanation:

|a|=\left\{\begin{array}{ccc}a&for\ a\geq0\\-a&for\ a

Put each value of x from the set {2, 3, 4, 5, 6}

to the equation y = 2|x - 4| + 3:

x = 2 → y = 2|2 - 4| + 3 = 2|-2| + 3 = 2(2) + 3 = 4 + 3 = 7 → (2, 7)

x = 3 → y = 2|3 - 4| + 3 = 2|-1| + 3 = 2(1) + 3 = 2 + 3 = 5 → (3, 5)

x = 4 → y = 2|4 - 4| + 3 = 2|0| + 3 = 2(0) + 3 = 0 + 3 = 3 → (4, 3)

x = 5 → y = 2|5 - 4| + 3 = 2|1| + 3 = 2(1) + 3 = 2 + 3 = 5 → (5, 5)

x = 6 → y = 2|6 - 4| + 3 = 2|2| + 3 = 2(2) + 3 = 4 + 3 = 7 → (6, 7)

Mark the points in the coordinates system.

The domain is only five numbers, therefore the graph of this function is only five points.

5 0
3 years ago
Read 2 more answers
Grandma's recipe for sugar cookies 1 cups butter 2 cups sugar 4 eggs 1/2 teaspoon baking powder 1 1/4 cups of flower 1/4 teaspoo
olasank [31]
Thank you............?
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