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RUDIKE [14]
3 years ago
14

Many employees screen gpa in addition to a variety of skills. Suppose a student is in the last semester of college and has a 2.6

8 gpa after 108 credit hours. If he is taking 12 credit hours in his last semester and gets a perfect 4.0 gpa, what will his overall gpa be? Is it possible to get his gpa up to 3.0 for graduation?
Mathematics
1 answer:
wel3 years ago
3 0

Answer:

  • Overall GPA=2.81
  • It is not possible to get his GPA to 3.0 for graduation.

Step-by-step explanation:

The Student already has a GPA of 2.68 after 108 credit hours.

If he is taking 12 credit hours in his last semester and gets a perfect 4.0 GPA

Total Credits Earned Before = 2.68 X 108=2894.4

Projected Credit to be earned = 12 X 4= 48 Credits

Total credit Hour= 108+12=120 Hours

His Cumulative GPA = Total credits earned ÷ Total Credit Hour

=\frac{2894.4+48}{120} =2.81

Since 2.81 is less than 3.00, it is not possible to get his GPA to 3.0 for graduation.

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Answer:

The surface area of the rectangular prism is 748 ft2.

Step-by-step explanation:

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8 0
2 years ago
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Given that (x+y+z)(xy+xz+yz)=18 and that x^2(y+z)+y^2(x+z)+z^2(x+y)=6 for real numbers x, y, and z, what is the value of xyz?
worty [1.4K]

Answer:

4

Step-by-step explanation:

(x+y+z)(xy+xz+yz)=18 Equation 1

x^2(y+z)+y^2(x+z)+z^2(x+y)=6 Equation 2

What is the value of xyz where each variable represents a real number?

Let's expand equation 1:

(x+y+z)(xy+xz+yz)=18

x(xy)+x(xz)+x(yz)+y(xy)+y(xz)+y(yz)+z(xy)+z(xz)+z(yz)=18

Simplify each term if can:

x^2y+x^2z+xyz+y^2x+xyz+y^2z+xyz+z^2x+z^2y=18

See if we can factor a little to get some of the left hand side of equation 2:

The first two terms have x^2 and if I factored x^2 from first two terms I would have x^2(y+z) which is the first term of left hand side of equation 2.

So let's see what happens if we gather the terms together that have the same variable squared together.

x^2y+x^2z+y^2x+y^2z+z^2y+z^2x+xyz+xyz+xyz=18

Factor the variable squared terms out of each binomial pairing:

x^2(y+z)+y^2(x+z)+z^2(y+x)+xyz+xyz+xyz=18

Replace the sum of those first three terms with what it equals which is 6 from the equation 2:

6+xyz+xyz+xyz=18

Combine like terms:

6+3xyz=18

Subtract 6 on both sides:

3xyz=12

Divide both sides by 3:

xyz=4

4 0
3 years ago
!MAGOR HELP!<br> Question and answers are in the pic
Simora [160]
The first one is correct (-2/3, -1/2, 7/12, 0.82) pls mark branliest
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