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RUDIKE [14]
4 years ago
14

Many employees screen gpa in addition to a variety of skills. Suppose a student is in the last semester of college and has a 2.6

8 gpa after 108 credit hours. If he is taking 12 credit hours in his last semester and gets a perfect 4.0 gpa, what will his overall gpa be? Is it possible to get his gpa up to 3.0 for graduation?
Mathematics
1 answer:
wel4 years ago
3 0

Answer:

  • Overall GPA=2.81
  • It is not possible to get his GPA to 3.0 for graduation.

Step-by-step explanation:

The Student already has a GPA of 2.68 after 108 credit hours.

If he is taking 12 credit hours in his last semester and gets a perfect 4.0 GPA

Total Credits Earned Before = 2.68 X 108=2894.4

Projected Credit to be earned = 12 X 4= 48 Credits

Total credit Hour= 108+12=120 Hours

His Cumulative GPA = Total credits earned ÷ Total Credit Hour

=\frac{2894.4+48}{120} =2.81

Since 2.81 is less than 3.00, it is not possible to get his GPA to 3.0 for graduation.

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It cost 5 dollars for a child ticket and 8 dollars for a adult ticket. Total tickets sold were 110 bringing in 820 dollars? How
omeli [17]

Number of child tickets bought is 20

<h3><u>Solution:</u></h3>

Given that It cost 5 dollars for a child ticket and 8 dollars for a adult ticket

cost of each child ticket = 5 dollars

cost of each adult ticket = 8 dollars

Let "c" be the number of child tickets bought

Let "a" be the number of adult tickets bought

Total tickets sold were 110 bringing in 820 dollars

<em>Number of child tickets bought + number of adult tickets bought = 110</em>

c + a = 110 ----- eqn 1

<em><u>Also we can frame a equation as:</u></em>

Number of child tickets bought x cost of each child ticket + number of adult tickets bought x cost of each adult ticket = 820

c \times 5 + a \times 8 = 820

5c + 8a = 820 -------- eqn 2

Let us solve eqn 1 and eqn 2 to find values of "c" and "a"

From eqn 1,

a = 110 - c  ------ eqn 3

Substitute eqn 3 in eqn 2

5c + 8(110 - c) = 820

5c + 880 - 8c = 820

-3c = - 60

c = 20

Therefore from eqn 3,

a = 110 - 20 = 90

a = 90

Therefore number of child tickets bought is 20

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VladimirAG [237]
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