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Aneli [31]
3 years ago
14

{(2,5),(7,3)} is the inverse relation of the function {(5,2),(3,7)} truth or false

Mathematics
1 answer:
dezoksy [38]3 years ago
7 0

frankly yes, because when you want inverse a function you must inverse it with line x=y

so when you inverse a function Df and Rf will convert together!

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What value of × is in the solution set of -5×-15>10+20×
vazorg [7]

Answer: x

Step-by-step explanation:

-5x-15>10+20x

Subtract 20x

-5x-20x-15>10

add 15

-5x-20x>10+15

Combine like terms

-25x>25\\

Divide by -25 (NOTE: When dividing or multiplying by negative numbers the inequality sign flips.)

x

5 0
3 years ago
David is filling five 3/4 quart bottles with a sports drink. His measuring cup only holds 1/4 quart. How many times will David n
OleMash [197]
Well if he is filling one 3/4 quart bottle, then he must fill his measuring cup 3 times, so just multiply it by 5, and you have 15.

David needs to fill the measuring cup 15 times.


7 0
3 years ago
Tricia listed her assets and liabilities.
kumpel [21]

Answer:

<u>The correct answer is A. Credit card bill and B. Car loan</u>

Step-by-step explanation:

Let's recall that we consider a personal or familiar liability an obligation to pay money you or your family owe to another person or financial institution like a bank. Liabilities can be classified according to the term, either short such as a credit card or loan from the bank with one-year term, or long such as a car loan or mortgage.

According to that definition, Tricia's liabilities are A. Credit card bill and B. Car loan.

6 0
3 years ago
Read 2 more answers
Which statements are true regarding the area of circles and sectors? Check all that apply.
AveGali [126]

Answer:

The correct options are a,b.

Step-by-step explanation:

The area of sector of a circle equals

Area of a sector = \theta r^{2}

where

\theta is the angle subtended at the center by the sector

r is the radius of circle

This indicates that area of the sector depends on:

1) Radius of circle

2) Angle  subtended at the center by the sector

3) Area of sector does not depend on pi.

Also if we know the area of the sector only  we cannot calculate area of area of whole triangle as we need one more information either angle of the sector and vice versa.

3 0
3 years ago
Read 2 more answers
A circle has the order pairs (-1, 2) (0, 1) (-2, -1) what is the equation . Show your work.
olga55 [171]
We know that:

(x-a)^2+(y-b)^2=r^2

is an equation of a circle.

When we substitute x and y (from the pairs we have), we'll get a system of equations:

\begin{cases}(-1-a)^2+(2-b)^2=r^2\\(0-a)^2+(1-b)^2=r^2\\(-2-a)^2+(-1-b)^2=r^2\end{cases}

and all we have to do is solve it for a, b and r.

There will be:

\begin{cases}(-1-a)^2+(2-b)^2=r^2\\(0-a)^2+(1-b)^2=r^2\\(-2-a)^2+(-1-b)^2=r^2\end{cases}\\\\\\&#10;\begin{cases}1+2a+a^2+4-4b+b^2=r^2\\a^2+1-2b+b^2=r^2\\4+4a+a^2+1+2b+b^2=r^2\end{cases}\\\\\\&#10;\begin{cases}a^2+b^2+2a-4b+5=r^2\\a^2+b^2-2b+1=r^2\\a^2+b^2+4a+2b+5=r^2\end{cases}\\\\\\&#10;

From equations (II) and (III) we have:

\begin{cases}a^2+b^2-2b+1=r^2\\a^2+b^2+4a+2b+5=r^2\end{cases}\\--------------(-)\\\\a^2+b^2-2b+1-a^2-b^2-4a-2b-5=r^2-r^2\\\\-4a-4b-4=0\qquad|:(-4)\\\\\boxed{-a-b-1=0}

and from (I) and (II):

\begin{cases}a^2+b^2+2a-4b+5=r^2\\a^2+b^2-2b+1=r^2\end{cases}\\--------------(-)\\\\a^2+b^2+2a-4b+5-a^2-b^2+2b-1=r^2-r^2\\\\2a-2b+4=0\qquad|:2\\\\\boxed{a-b+2=0}

Now we can easly calculate a and b:

\begin{cases}-a-b-1=0\\a-b+2=0\end{cases}\\--------(+)\\\\-a-b-1+a-b+2=0+0\\\\-2b+1=0\\\\-2b=-1\qquad|:(-2)\\\\\boxed{b=\frac{1}{2}}\\\\\\\\a-b+2=0\\\\\\a-\dfrac{1}{2}+2=0\\\\\\a+\dfrac{3}{2}=0\\\\\\\boxed{a=-\frac{3}{2}}

Finally we calculate r^2:

a^2+b^2-2b+1=r^2\\\\\\\left(-\dfrac{3}{2}\right)^2+\left(\dfrac{1}{2}\right)^2-2\cdot\dfrac{1}{2}+1=r^2\\\\\\\dfrac{9}{4}+\dfrac{1}{4}-1+1=r^2\\\\\\\dfrac{10}{4}=r^2\\\\\\\boxed{r^2=\frac{5}{2}}

And the equation of the circle is:

(x-a)^2+(y-b)^2=r^2\\\\\\\left(x-\left(-\dfrac{3}{2}\right)\right)^2+\left(y-\dfrac{1}{2}\right)^2=\dfrac{5}{2}\\\\\\\boxed{\left(x+\dfrac{3}{2}\right)^2+\left(y-\dfrac{1}{2}\right)^2=\dfrac{5}{2}}
7 0
3 years ago
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