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MArishka [77]
3 years ago
11

Javier is also kayaking, he can go 1 mild in 2/3 of an hour. How far can he go at this rate in 3 hours?

Mathematics
1 answer:
luda_lava [24]3 years ago
4 0

Answer:

The distance cover by Javier in 3 hours is 4.5 miles

Step-by-step explanation:

Given as :

The distance cover by Javier in \frac{2}{3} hour = 1 mile

Let The distance cover by Javier in 3 hours = x miles

Applying unitary method, we get

∵ In  \frac{2}{3} hour , distance cover by Javier = 1 mile

So, In 1 hour , distance cover by Javier = \frac{1}{\frac{2}{3}} mile = \frac{3}{2} mile

Or,  In 1 hour, distance cover by Javier = 1.5 miles

∴  In 3 hours , distance cover by Javier = 1.5 miles × 3

i.e x = 4.5 miles

So, The distance cover by Javier in 3 hours = x = 4.5 miles

Hence, The distance cover by Javier in 3 hours is 4.5 miles  Answer

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I note (a,b,c) the result of a quarters, b dimes and c pennies:


2 solutions:
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106=( 0, 0, 106) but : 100= 0*25+ 0*10+ 100
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106=( 0, 2, 86) but : 100= 0*25+ 2*10+ 80
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106=( 0, 4, 66) but : 100= 0*25+ 4*10+ 60
106=( 0, 5, 56) but : 100= 0*25+ 5*10+ 50
106=( 0, 6, 46) but : 100= 0*25+ 6*10+ 40
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106=( 0, 8, 26) but : 100= 0*25+ 8*10+ 20
106=( 0, 9, 16) but : 100= 0*25+ 9*10+ 10
106=( 0, 10, 6) but : 100= 0*25+ 10*10+ 0
106=( 1, 0, 81) but : 100= 1*25+ 0*10+ 75
106=( 1, 1, 71) but : 100= 1*25+ 1*10+ 65
106=( 1, 2, 61) but : 100= 1*25+ 2*10+ 55
106=( 1, 3, 51) but : 100= 1*25+ 3*10+ 45
106=( 1, 4, 41) but : 100= 1*25+ 4*10+ 35
106=( 1, 5, 31) but : 100= 1*25+ 5*10+ 25
106=( 1, 6, 21) but : 100= 1*25+ 6*10+ 15
106=( 1, 7, 11) but : 100= 1*25+ 7*10+ 5
106=( 1, 8, 1) is good
106=( 2, 0, 56) but : 100= 2*25+ 0*10+ 50
106=( 2, 1, 46) but : 100= 2*25+ 1*10+ 40
106=( 2, 2, 36) but : 100= 2*25+ 2*10+ 30
106=( 2, 3, 26) but : 100= 2*25+ 3*10+ 20
106=( 2, 4, 16) but : 100= 2*25+ 4*10+ 10
106=( 2, 5, 6) but : 100= 2*25+ 5*10+ 0
106=( 3, 0, 31) but : 100= 3*25+ 0*10+ 25
106=( 3, 1, 21) but : 100= 3*25+ 1*10+ 15
106=( 3, 2, 11) but : 100= 3*25+ 2*10+ 5
106=( 3, 3, 1) is good
106=( 4, 0, 6) but : 100= 4*25+ 0*10+ 0






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