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BARSIC [14]
3 years ago
11

Can someone please help me

Mathematics
1 answer:
exis [7]3 years ago
4 0
It’ll be B, think about it logically, u have to make the fraction have the same denominator, then u have to do the opposite of the equation (here u have x + *the fraction* meaning u have take that fraction away from the total fraction)
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At the local aquarium there are 10 dolphins 8 penguins and 4 whales what is the ratio of penguins to whales
juin [17]
A ratio compares two quantities.

penguins = 8
whales = 4

8:4 , now simplify

8/4 = 2
4/4 = 1

2:1 is the ratio.

Final answer: 2:1
5 0
3 years ago
Read 2 more answers
‍ ‍ ‍ ‍ ‍ ‍ ‍ ‍ ‍ ‍ ‍ ‍ ‍ ‍ ‍ ‍ ‍
guajiro [1.7K]

Answer:

x < 6

Step-by-step explanation:

5x < 30

5x/5 < 30/5

x < 6

5 0
3 years ago
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What is the answer to my question? No links please. Urgent.
babunello [35]

Answer:

57cm^3

i belive this is right.

6 0
3 years ago
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Write an equation of a parabola in standard form that has a vertex of (-3,-4) and passes through (1,4)
Bumek [7]

As we know vertex -

y=a(x+3)^2-4

Passes through (1,4). Substitute x = 1 and y = 4

4=a(1+3)^2-4\\4=a(4)^2-4\\4=16a-4\\4+4=16a\\16a=8\\a=\frac{8}{16}\\a=\frac{1}{2}

Therefore the vertex equation is y=\frac{1}{2}(x+3)^2-4

Since you want the "standard" form then..

y=\frac{1}{2}(x^2+6x+1)\\y=\frac{1}{2}x^2+3x+\frac{1}{2}

So the standard form is 1/2x^2 + 3x + 1/2

6 0
3 years ago
Plss answer!! <br>MERRY Christmas!!! <br>Critical Question. AAAAA​
liberstina [14]

Answer:

Step-by-step explanation:

abc = 1

We have to prove that,

\frac{1}{1+a+b^{-1}}+\frac{1}{1+b+c^{-1}}+\frac{1}{1+c+a^{-1}}=1

We take left hand side of the given equation and solve it,

\frac{1}{1+a+\frac{1}{b}}+\frac{1}{1+b+\frac{1}{c}}+\frac{1}{1+c+\frac{1}{a}}

Since, abc = 1,

\frac{1}{c}=ab and c = \frac{1}{ab}

By substituting these values in the expression,

\frac{1}{1+a+\frac{1}{b}}+\frac{1}{1+b+\frac{1}{c}}+\frac{1}{1+c+\frac{1}{a}}=\frac{1}{1+a+\frac{1}{b}}+\frac{1}{1+b+ab}+\frac{1}{1+\frac{1}{ab}+\frac{1}{a}}

                                       =\frac{b}{b+ab+1}+\frac{1}{1+b+ab}+\frac{ab}{ab+1+b}

                                       =\frac{1+b+ab}{1+b+ab}

                                       =1

Which equal to the right hand side of the equation.

Hence, \frac{1}{1+a+b^{-1}}+\frac{1}{1+b+c^{-1}}+\frac{1}{1+c+a^{-1}}=1

5 0
3 years ago
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