71.700 rounded to the nearest hundredth

Mathematics

2 answers:

Vsevolod [243]3 years ago

8 0

Answer:

71.70 for sure

Anna35 [415]3 years ago

4 0

Answer:

71.70

Step-by-step explanation:

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The histogram to the right represents the weights (in pounds) of members of a certain high-school math team.

kupik [55]

Answer: There are total 20 team members.

Step-by-step explanation:

Ans: There are total 20 team members.

Concept: In the given picture a graph shows the relation between the number of people and their weight. The y-axis shows the number of team members and the x-axis shows the weight of those particular number of members. So, just notice the number of members corresponding to all the given weights and add them.

Solution step by step

Step 1: Members corresponding to 115kg

There are total 5 members having 115kg weight.

Step 2: Members corresponding to 135kg

There are total 3 members having 135kg weight.

Step 3: Members corresponding to 155kg

There are total 2 members having 155kg weight.

Step 4: Members corresponding to 175kg

There are total 0 members having 175kg weight.

Step 5: Members corresponding to 195kg

There are total 3 members having 195kg weight.

Step 6: Members corresponding to 215kg

There are total 4 members having 215kg weight.

Step 7: Members corresponding to 235kg

There are total 3 members having 235kg weight.

Step 8: Add the number of members

The total number of members are 5+3+2+0+3+4+3=20

So, the total number of members are 20.

#SPJ10

5 0

1 year ago

A simple die is thrown 100 times and the number five appears 14 times. Find the experimental probability of throwing a five, giv

mario62 [17]

Answer:

The experimental probability of throwing a five is 0.087.

Step-by-step explanation:

Given:

Number of trials (n) = 100

Number of times 5 appears (x) = 14

Let the event of occurrence of 5 be success and the probability represented by 'p'. So, all the other numbers occurrence is failure and its probability is represented as 'q'.

Probability of success is given as:

$p=\frac{Number\ of\ favorable\ events}{Total\ number\ of\ outcomes}$