Answer:
A:Scientific evidence must be reported, verified, and accepted by the scientific community
B:amino acid
Explanation:
aaaay another flvser
(hi, i dont know about this one personally, but i found an answer somewhere else on the internet thatll hopefully help u)
Answer: They consist of long chains of C, H, and O.
Explanation:
In terms of chemical composition, lipids differ from nucleic acids and proteins because they mostly just contain carbon, hydrogen, and oxygen (except for phospholipids which of course contain phosphorous). In addition to those elements, proteins contain nitrogen and sulfur, and nucleic acids contain nitrogen and phosphorous.
Carbohydrates share the C, H, and O composition as lipids, but they differ in structure. Lipids are generally exist as triglycerides, which consist of a triple hydroxyl alcohol (glycerol) that has bonded to three long-chain carboxylic acids (fatty acids) in a triple condensation reaction. Carbohydrates on the other hand are made of carbon ring structures that either remain alone or polymerize into long polysaccharide chains.
Cancer or cell death could happen I got it right in my test
The process of fusing two or more DNA molecules to produce a hybrid is known as recombinant DNA. Restrictions endonucleases and ligases are two classes of enzymes that enable the technique.
When a restriction endonuclease detects a particular DNA sequence, it makes cuts inside or near that sequence. The recognition sequence of a restriction enzyme will haphazardly appear on every (1–4)n bases along a random DNA chain. The equation states how many fragments ends (measured in moles) are produced when a restriction enzyme cuts DNA.
Moles of DNA ends =2x(grams of DNA)/(number of bp)(660 g/mol / bp).
The equation describes how many ends are produced when circular DNA is digested by a restriction enzyme.
Mole ends=2x(moles DNA)x number of restriction sites.
The following equation can be used to determine how many ends are produced during the digestion of a linear molecule by a restriction endonuclease.
Mole ends=2x(molesDNA)number of restriction sites +[2x(moles of DNA)].
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