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lilavasa [31]
3 years ago
11

Evaluate the following when a=2 b=-3 and c=4:

Mathematics
2 answers:
Vaselesa [24]3 years ago
8 0

Answer:

A. 41

Step-by-step explanation:

5a - b² + 2c(a-b)

Put a = 2, b = -3, and c = 4.

5(2) - (-3)² + 2(4)(2-(-3))

Evaluate.

10 - 9 + 2(4)(2+3)

10 - 9 + 8(5)

10 - 9 + 40

1 + 40

= 41

algol [13]3 years ago
7 0

Answer:

41

Step-by-step explanation:

Given that,

a = 2 \\ b =  - 3 \\ c = 4

Let's solve now,

5a -  {b}^{2}  + 2c(a - b) \\ 5 \times 2 - ( { - 3}^{2} ) + 2 \times 4(2 - ( - 3)) \\ 10 - ( - 3 \times  - 3) + 8(2 + 3) \\ 10 - 9 + 8 \times 5 \\ 10 - 9 + 40 \\  1 + 40 \\  = 41

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Let's solve your equation step-by-step.

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Step 1: Simplify both sides of the equation.

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Step 3: Add 4 to both sides.

−4 + 4 = 19 + 4

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Answer:

There are no solutions.

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Given the following system, what would be the best way to start slowing the system?
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