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Leno4ka [110]
2 years ago
13

When factored into primes 2020=2^2*5^1*101^1.How many positive non-prime factors does 2020 have?

Mathematics
1 answer:
valentinak56 [21]2 years ago
3 0

Answer:

balls

Step-by-step explanation:

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A bag contains 6 green marbles, 9 red marbles, 7 white marbles, and 3 black marbles. What is the probability of drawing a red ma
bonufazy [111]

Well if you add them all together you would get 25. You would have 9/25 red marbles. Then you would take 9 and divide it by 25 and get 0.36 and if you move the decimal over 2 places you’ll get 36%

6 0
2 years ago
Anna received a gift card for $25 to an art store. The table shows the cost of the items.
Kaylis [27]

Answer:

7.99+2(1.09)+3(2.75)+x =25

Step-by-step explanation:

what's given are the prices of the canvas, brushes, and bottles of pain. 7.99 represents the one canvas Anna is buying, 2(1.09) represents the 2 brushes, and 3(2.75) represents the bottle of paints. Now what's left is x and x represents the amount of money left on the gift card. The gift card is $25 in total so that's why at the end of the equation it equals to $25.

4 0
3 years ago
Determine the probability of selecting a two-child family with one boy and one girl assuming boys and girls are equally likely
Fittoniya [83]

Using the binomial distribution, it is found that there is a 0.5 = 50% probability of selecting a two-child family with one boy and one girl.

For each child, there are only two possible outcomes, either it is a boy, or it is a girl. The probability of a child being a boy or being a girl is independent of any other child, which means that the binomial distribution is used to solve this question.

Binomial probability distribution

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

C_{n,x} = \frac{n!}{x!(n-x)!}

The parameters are:

  • x is the number of successes.
  • n is the number of trials.
  • p is the probability of a success on a single trial.

In this problem:

  • Two children, hence n = 2.
  • Equally as likely to be a boy or a girl, hence p = 0.5.

The probability of one of each is P(X = 1), hence:

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 1) = C_{2,1}.(0.5)^{1}.(0.5)^{1} = 0.5

0.5 = 50% probability of selecting a two-child family with one boy and one girl.

A similar problem is given at brainly.com/question/24863377

3 0
2 years ago
Light travels about 168,000 mi/s. The function d(t) = 168,000t gives the distance d(t) in miles that light travels in t seconds.
Yuliya22 [10]

Answer:

The nuclear utility environment is one of strict cost control under prescriptive regulations and increasing public scrutiny. This paper presents the results of A Total Quality approach, by a dedicated team, that addresses the need for increased on-site spent fuel storage in this environment. Innovations to spent fuel pool reracking, driven by utilities' specific technical needs and shrinking budgets, have resulted in both product improvements and lower prices. A Total Quality approach to the entire turnkey project is taken, thereby creating synergism and process efficiency in each of the major phases of the project: design and analysis, licensing, fabrication, installation and disposal. Specific technical advances and the proven quality of the team members minimizes risk to the utility and its shareholders and provides a complete, cost effective service. Proper evaluation of spent fuel storage methods and vendors requires a full understanding of currently available customer driven initiatives that reduce cost while improving quality. In all phases of a spent fuel reracking project, from new rack design and analysis through old rack disposal, the integration of diverse experts, at all levels and throughout all phases of a reracking project, better serves utility needs. This Total Quality environment in conjunction with many technical improvements results in a higher quality product at a lower cost

The prediction of minor actinides amounts accumulated in the spent fuel in China

International Nuclear Information System (INIS)

Zhou Peide

2000-01-01

The amounts of the Minor Actinides accumulated in the spent fuel are predicted according to the Nuclear Power Plant development plan envisaged in China. The Minor Actinides generated in the spent fuel unloaded from a typical PWR per year are calculated. The decay characteristics of the Minor Actinides during storage and cooling period are also calculated. At last, the Minor Actinides amounts accumulated in all spent fuel which were unloaded before sometime are given

8 0
3 years ago
6m−7)⋅4=left parenthesis, 6, m, minus, 7, right parenthesis, dot, 4, equals ¿Atorado?
mars1129 [50]

Answer:

24m - 28

Step-by-step explanation:

Given the expression (6m−7)⋅4, we are to simplify it. Using the distributive law;

A(B+C) = AB + AC [A is distributed over B and C]

For the expression (6m−7)⋅4, we will distribute 4 over 6m and -7 as shown;

(6m−7)⋅4 = 4(6m) - 4(7)

(6m−7)⋅4 = 24m - 28

Hence (6m−7)⋅4 = 24m - 28

7 0
3 years ago
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