Question

Lera brought a watermelon that weighed b kg to a party. Nick brought a box of candies. How much is the weight of the box of candies greater than the weight of the watermelon if the weight of the watermelon is 2/5 of the weight of the box of candies?

Answer 1

Answer:

1.5b (kg)

Step-by-step explanation:

Let's begin by listing out the variables we were given:

weight of the watermelon = b (kg),

weight of watermelon = (2/5) * weight of candies

weight of candies = 1 ÷ (2/5) = 1 ÷ 0.4

weight of candies = 2.5b (kg)

How much is the weight of the box of candies greater than the weight of the watermelon is given by:

weight of the box of candies - weight of watermelon= 2.5b - b = 1.5b (kg)

Therefore, the weight of the box of candies is greater than the weight of the watermelon by 1.5b (kg)