1x+ 3y = -12x + 2y = 6
+12x +12x
13x + 3y = 2y = 6
+3y +3y
13x = 5y = 6
13x = 5y and 5y = 6
Answer:
P(x < 3) = 0.1971
Explanation:
To calculate the probability that x babies weigh more than 20 pounds, we will use the binomial distribution, so it can be calculated as:

So, replacing n = 16 and p = 0.25, we get that the probability is equal to
P(x) = 16Cx (0.25)^x (1 - 0.25)^(16 - x)

Now, the probability that fewer than three weights more than 20 pounds are equal to

Then
P(x < 3) = 0.01 + 0.0535 + 0.1336
P(x < 3) = 0.1971
Therefore, the answer is
P(x < 3) = 0.1971
You have to do e=me squared and find the pathagorean theorem for the mass of the exponent cubed to the root of log
100 ; you are adding 20 every time, therefore if you add 80 plus 20 you get 100. :)
591,912 rounded to the nearest thousands = 592,000