Answer:
yes that correct
Step-by-step explanation:
I just took the test. The answer is y=5/2 x+5
Let's do
![\\ \rm\dashrightarrow y=\dfrac{3}{x-h}+k](https://tex.z-dn.net/?f=%5C%5C%20%5Crm%5Cdashrightarrow%20y%3D%5Cdfrac%7B3%7D%7Bx-h%7D%2Bk)
Release k for some while
If
So
So vertical asymptote is at origin now
It mentioned that it's at x=-5 so we need to change x
![\\ \rm\dashrightarrow y=\dfrac{3}{x-(-5)}](https://tex.z-dn.net/?f=%5C%5C%20%5Crm%5Cdashrightarrow%20y%3D%5Cdfrac%7B3%7D%7Bx-%28-5%29%7D)
![\\ \rm\dashrightarrow y=\dfrac{3}{x+5}](https://tex.z-dn.net/?f=%5C%5C%20%5Crm%5Cdashrightarrow%20y%3D%5Cdfrac%7B3%7D%7Bx%2B5%7D)
- Vertical asymptote at x=-5
Now
- for k=0 horizontal asymptote at origin
But it's given
Same put y=12 in place of k
![\\ \rm\dashrightarrow y=\dfrac{3}{x+5}+12](https://tex.z-dn.net/?f=%5C%5C%20%5Crm%5Cdashrightarrow%20y%3D%5Cdfrac%7B3%7D%7Bx%2B5%7D%2B12)
Graph attached for verification
It Should be 15/x for what I see in my notes