Question

MAX POINTS

Answer 1

Let's do

$\\ \rm\dashrightarrow y=\dfrac{3}{x-h}+k$

Release k for some while

If

• we take h=0

So

• y=3/x

So vertical asymptote is at origin now

It mentioned that it's at x=-5 so we need to change x

• put -5 in place of h

$\\ \rm\dashrightarrow y=\dfrac{3}{x-(-5)}$

$\\ \rm\dashrightarrow y=\dfrac{3}{x+5}$

• Vertical asymptote at x=-5

Now

• for k=0 horizontal asymptote at origin

But it's given

• y is at 12

Same put y=12 in place of k

$\\ \rm\dashrightarrow y=\dfrac{3}{x+5}+12$

• h=-5
• k=12

Graph attached for verification