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3 years ago

NEED HELP PLEASE!!!!!!!!!!!!!!!!!!!!!!!!!!

1 answer:

5 0

Let the price of a bag of balloon=x and the price of a roll of crepe paper =y
5x+2y=38
12x+14y=128
These are the equation you get from the question
5x+2y=38
-5x -5x
2y=38-5x divide both side by 2
y=19-5/2x

  12x+14y=128 plug in the y
12x+14(19-5/2x)=128
12x+266-35x=128
-23x+266=128
-266 -266
-23x=-138 divide both side by -23
x=6 this will be the price of a bag of balloon

5x+2y=38 plug in x
5(6)+2y=38
30+2y=38
-30 -30
2y=8 divide both side by 2
y=4 this will be the price of a roll of crepe paper

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Conference A and conference B each have 10 football teams. The table shows the number of football games that each team in the tw

babymother [125]

Answer with explanation:

1.Mean of a Data set

$=\frac{\text{Sum of all the observation}}{\text{total number of observation}}$

$=\frac{10+9+11+8+10+12+2+7+8+0+12+10+8+11+3+12+6+7+4+3}{20}\\\\=\frac{153}{20}\\\\=7.65$

2. Range = Maximum value in two conferences - Minimum value in two conference

= 12 - 0

=12

The mean number of wins for teams from the two conferences is 7.65.

The range in wins is 12.

3 0

3 years ago

Read 2 more answers

A company produces and sells widgets and gizmos. In January the company sold 350 items for a total of $9,000. If each widget sol

iren [92.7K]

Answer:

The company sold 100 widgets and 250 gizmos.

Step-by-step explanation:

Let $x_1$ be the number of widgets sold and $x_2$ be the number of gizmos sold.

We are told that the company sold 350 items. We can represent this information in an equation as:

$x_1+x_2=350...(1)$

We have been given that a each widget sold for $35 and each gizmo sold for $22. The company sold 350 items for a total of $9,000.

We can represent this information in an equation as:

$35x_1+22x_2=9,000...(2)$

From equation (1), we will get:

$x_2=350-x_1$

Substitute this value in equation (2):

$35x_1+22(350-x_1)=9,000$

$35x_1+7,700-22x_1=9,000$

$13x_1+7,700=9,000$

$13x_1+7,700-7,700=9,000-7,700$

$13x_1=1,300$

$\frac{13x_1}{13}=\frac{1,300}{13}$

$x_1=100$

Therefore, the company sold 100 widgets.

Substitute $x_1=100$ in equation (1):

$100+x_2=350$

$100-100+x_2=350-100$

$x_2=250$

Therefore, the company sold 250 gizmos.

3 0

3 years ago

Read 2 more answers

A basketball team playd 64 games they won 28 more than they lost

natka813 [3]

They won 46 games. They lost 18 games.

7 0

3 years ago

Solve by elimination 7x+7y=-7 -10x-7y=28

Zarrin [17]

Answer:

x = - 7, y = 6

Step-by-step explanation:

7x + 7y = - 7 -----> equation 1

- 10x - 7y = 28 -----> equation 2

Add equations 1 & 2,

7x + 7y = - 7

- 10x - 7y = 28

___________

- 3x + 0 = 21

- 3x = 21

x = 21 / - 3

x = - 7

Substitute x = - 7 in equation 1,

7x + 7y = - 7

7y + 7x = - 7

7y + 7 ( - 7 ) = - 7

7y - 49 = - 7

7y = - 7 + 49

7y = 42

y = 42 / 7

y = 6

7 0

2 years ago

Read 2 more answers

In a city school, 70% of students have blue eyes, 45% have dark hair, and 30% have blue eyes and dark hair. What is the probabil

Travka [436]

Answer:

The correct answer option is 43%.

Step-by-step explanation:

We are given that 70% of students have blue eyes, 45% have dark hair, and 30% have blue eyes and dark hair.

We are to find the probability of a student getting selected will have dark hair with blue eyes.

P(D|B) = P(D∩B) / P(B)

Substituting the given values in it to get:

P(D|B) = 0.3 / 0.7 = 0.428

Rounding it to the nearest whole percent we get:

0.428 × 100 = 42.8% ≈ 43%

4 0

2 years ago