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amid [387]
3 years ago
10

What is the smallest solution to the equation 2/3 x^2=24

Mathematics
1 answer:
True [87]3 years ago
7 0

Answer:

The smallest solution is -6

Step-by-step explanation:

2/3 x^2=24

Multiply by 3/2 on each side

3/2 *2/3 x^2=24 *3/2

x^2 = 36

Take the square root of each side

sqrt(x^2) = ±sqrt(36)

x = ±6

x = -6, 6

The smallest solution is -6

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Bethany Christian school performed a play both on Thursday and Saturday nights. three times as many people attended on Saturday
lesya [120]

Answer:

816 people attended on Saturday night.

Step-by-step explanation:

8 0
3 years ago
Solve 2csc^2x-2cscx-1=0 <br> for 0° ≤ x ≤ 360°
umka21 [38]

Answer:

Step-by-step explanation:

2 csc²x-2 csc x-1=0

or

\frac{2}{sin^2x} -\frac{2}{sin x} -1=0\\multiply~by~sin^2x\\2-2sin~x-sin^2x=0\\sin^2x+2sinx-2=0\\sin ~x=\frac{-2 \pm\sqrt{2^2-4*1*(-2)} }{2*1} \\=\frac{-2 \pm\sqrt{4+8} }{2} \\=\frac{-2 \pm\sqrt{4*3} }{2} \\=\frac{-2 \pm2\sqrt{3} }{2} \\=-1\pm\sqrt{3} \\|sin~x| \le ~1\\so~sin~x=-1+\sqrt{3} \\sin~x=\sqrt{3} -1\\x=sin^{-1}(\sqrt{3} -1) \approx 47.06^\circ,180-47.06\\or~x=47.06^\circ,132.94^\circ

6 0
2 years ago
Write the equation for the vertical line that passes through the point (5,-2)
amid [387]

If it's just a vertical line, then it could be displayed as: x = 5.

A vertical line is not actually a function, and because of such, the entire line is just the value of the x value, as it will never have enough x value.


4 0
2 years ago
If EF = 2x+13, FG = 20, and EG = 71 what's the value of x​
klemol [59]

Answer:

<h2>x = 19</h2><h2></h2>

Step-by-step explanation:

|<----------------- 71 ----------------------->|

E-----------------------F---------------------G

       2x + 13                 20

find: x

EF + FG = DG

2x + 13 + 20 = 71

2x = 71 - 20 - 13

x = 38 / 2

x = 19

6 0
2 years ago
A student wants to construct the inscribed circle of a triangle. What is the first step she should take?
Leviafan [203]
D) construction of the angle bisector.
So if you have a triangle that is not equilateral the perpendicular bisectors would not work so you need angle bisectors.
I have drawn a diagram
The green is the angle bisectors and the yellow the perpendicular bisectors.
You can see the problem straight away

4 0
3 years ago
Read 2 more answers
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