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pishuonlain [190]
3 years ago
6

Solve the following equal 12x - 11 -23​

Mathematics
1 answer:
jeka57 [31]3 years ago
8 0

Answer:

12x -34

Step-by-step explanation:

Combine values

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Answer:

5^9 is not a square number

Step-by-step explanation:

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-3 - 8 = 19<br> —3x - 2 = 25
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Esmerelda is a math student who needs to gather a sample of 10 participants to conduct a survey about U.S. residents. She asks h
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A convenience sample is made up of people who are easy to reach so it would be B

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X -&gt; ∞ * (sqrt(x - a) - sqrt(bx))​
QveST [7]

Simplify the limand in the following way.

\displaystyle \lim_{x\to\infty} \left(\sqrt{x-a} - \sqrt{bx}\right) = \lim_{x\to\infty} \dfrac{\left(\sqrt{x-a}\right)^2 - \left(\sqrt{bx}\right)^2}{\sqrt{x-a} + \sqrt{bx}} \\\\ ~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~ = \lim_{x\to\infty} \frac{(x-a) - bx}{\sqrt x \left(\sqrt{1-\frac ax} + \sqrt b\right)} \\\\ ~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~ = \lim_{x\to\infty} \frac{(1-b)\sqrt x - \frac a{\sqrt x}}{\sqrt{1 - \frac ax} + \sqrt b}

Now,

\displaystyle \lim_{x\to\infty} \frac a{\sqrt x} = 0

\displaystyle \lim_{x\to\infty} \sqrt{1-\frac ax} = \sqrt{1-\lim_{x\to\infty}\frac ax}} = \sqrt1 = 1

\implies \displaystyle \lim_{x\to\infty} \left(\sqrt{x-a} - \sqrt{bx}\right) = \frac{1-b}{\sqrt b} \lim_{x\to\infty} \sqrt x

and therefore

\displaystyle \lim_{x\to\infty} \left(\sqrt{x-a} - \sqrt{bx}\right) = \begin{cases} 0 & \text{if } b = 1 \\ -\infty & \text{if } b > 1\end{cases}

and does not exist otherwise.

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2 years ago
a theme park in florida wants to attract more viewers. they post a survey on a travel website which attractions they would like
ioda

Answer:

The target population of the survey are travelers vacationing.

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3 years ago
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