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andriy [413]
3 years ago
9

Samantha was scanning photos she was scanned 123 but still has 296 left to scan how many pictures did she star with define a var

iable and write an equation solve the equation algebraically and check the solution
Mathematics
2 answers:
Free_Kalibri [48]3 years ago
7 0
X=total photos
X-123=296
+123 +123
X=419
Inessa [10]3 years ago
7 0
<em><u>Let the total no.of photos be "X"
Given,
no.of photos scanned=123
no.of photos left=296
equation is</u> X-123=296
                  X=296+123
                  X=419
Therefore total no.of photos =419
<u>

Hope this helps u!!!!!!!!!!</u>


</em>
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A farmer has a field in the shape of a triangle. The farmer has asked the manufacturing class at your school to build a metal fe
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Answer:

<em>Fencing required = 1586 m</em>

Step-by-step explanation:

The given statements can be thought of a triangle \triangle ABC as shown in the diagram attached.

A be the 1st vertex, B be the 2nd vertex and C be the 3rd vertex.

Distance between 1st and 2nd vertex, AB = 435 m

Distance between 2nd and 3rd vertex, AC = 656 m

\angle A =49^\circ

To find:

Fencing required for the triangular field.

Solution:

Here, we know two sides of a triangle and the angle between them.

To find the fencing or perimeter of the triangle, we need the third side.

Let us use <em>Cosine Rule </em>to find the third side.

Formula for cosine rule:

cos A = \dfrac{b^{2}+c^{2}-a^{2}}{2bc}

Where  

a is the side opposite to \angle A

b is the side opposite to \angle B

c is the side opposite to \angle C

\Rightarrow cos 49^\circ = \dfrac{656^{2}+435^{2}-BC^{2}}{2\times 435\times 656}\\\Rightarrow BC^2 = 430336+189225-2 (435)(656)cos49^\circ\\\Rightarrow BC^2 = 430336+189225-570720\times cos49^\circ\\\Rightarrow BC^2 =619561-570720\times cos49^\circ\\\Rightarrow BC \approx 495\ m

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<em></em>

<em>Fencing required = 1586 m</em>

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3 years ago
How do write fifty and six hundredths in standard form
BaLLatris [955]
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Answer:

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Step-by-step explanation:

Conduct a test to determine whether the true proportion of interest is higher than 0.7.

This means that the null hypothesis is: H_{0}: p = 0.7

And the alternate hypothesis is: H_{a}: p > 0.7

The test statistic is:

z = \frac{X - \mu}{\frac{\sigma}{\sqrt{n}}}

In which X is the sample mean, \mu is the value tested at the null hypothesis, \sigma is the standard deviation and n is the size of the sample.

0.7 is tested at the null hypothesis:

This means that \mu = 0.7, \sigma = \sqrt{0.7*0.3}

The sociologist found that 375 of the 500 travelers randomly selected and interviewed indicated that the airports were safe.

This means that n = 500, X = \frac{375}{500} = 0.75

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Probability of z being larger than 2.44, that is, a proportion larger than 0.75.

This is, looking at the z-table, 1 subtracted by the pvalue of Z = 2.44. S

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3 years ago
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p = 13 / (1/2)

p = 13 * 2/1

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so the value of p is 26

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3 years ago
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