Answer:
D. The work shown above is correct, and
may not be simplified further.
Step-by-step explanation:
![\sqrt[4]{y^{23} } = \sqrt[4]{y^4 . y^4 . y^4.y^4.y^3}](https://tex.z-dn.net/?f=%5Csqrt%5B4%5D%7By%5E%7B23%7D%20%7D%20%3D%20%5Csqrt%5B4%5D%7By%5E4%20.%20y%5E4%20.%20y%5E4.y%5E4.y%5E3%7D)
![\sqrt[4]{y^4. y^4.y^4. y^4.y^3} = y^5 . \sqrt[4]{y^3}](https://tex.z-dn.net/?f=%5Csqrt%5B4%5D%7By%5E4.%20y%5E4.y%5E4.%20y%5E4.y%5E3%7D%20%3D%20y%5E5%20.%20%5Csqrt%5B4%5D%7By%5E3%7D)
When we simplify, we get
![\sqrt[4]{y^{23} } = y^5.\sqrt[4]{y^3}](https://tex.z-dn.net/?f=%5Csqrt%5B4%5D%7By%5E%7B23%7D%20%7D%20%3D%20y%5E5.%5Csqrt%5B4%5D%7By%5E3%7D)
The answer: D. The work shown above is correct, and
may not be simplified further.
Thank you.
Since the new slope would be calculated to -3, the equations are neither parallel or perpendicular in accordance to each other.
Answer:
39 sq cm
Step-by-step explanation:
Ok. Since ΔAED is isosceles, then the height of the trapezoid is 3 cm
One base is 16 and the other base is 16 - 3 - 3 = 10.
A = 1/2 h(
+
) where
and
are lengths of the bases
A = 1/2(3)(10 + 16)
= 1/2(3)(26)
= 39 sq cm
Answer: 9/10 is the answer.