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andriy [413]
3 years ago
9

Samantha was scanning photos she was scanned 123 but still has 296 left to scan how many pictures did she star with define a var

iable and write an equation solve the equation algebraically and check the solution
Mathematics
2 answers:
Free_Kalibri [48]3 years ago
7 0
X=total photos
X-123=296
+123 +123
X=419
Inessa [10]3 years ago
7 0
<em><u>Let the total no.of photos be "X"
Given,
no.of photos scanned=123
no.of photos left=296
equation is</u> X-123=296
                  X=296+123
                  X=419
Therefore total no.of photos =419
<u>

Hope this helps u!!!!!!!!!!</u>


</em>
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How much will the taxi driver earn if he takes one passenger 4.8 miles and another passenger 7.3 miles? Explain your process.
Bezzdna [24]

Answer:

35.225 I believe

Step-by-step explanation:

You can always check on Slader.

4 0
3 years ago
4)In order to set rates, an insurance company is trying to estimate the number of sick daysthat full time workers at an auto rep
bagirrra123 [75]

Answer:

A sample of 18 is required.

Step-by-step explanation:

We have that to find our \alpha level, that is the subtraction of 1 by the confidence interval divided by 2. So:

\alpha = \frac{1 - 0.92}{2} = 0.04

Now, we have to find z in the Z-table as such z has a p-value of 1 - \alpha.

That is z with a pvalue of 1 - 0.04 = 0.96, so Z = 1.88.

Now, find the margin of error M as such

M = z\frac{\sigma}{\sqrt{n}}

In which \sigma is the standard deviation of the population and n is the size of the sample.

A previous study indicated that the standard deviation was 2.2 days.

This means that \sigma = 2.2

How large a sample must be selected if the company wants to be 92% confident that the true mean differs from the sample mean by no more than 1 day?

This is n for which M = 1. So

M = z\frac{\sigma}{\sqrt{n}}

1 = 1.88\frac{2.2}{\sqrt{n}}

\sqrt{n} = 1.88*2.2

(\sqrt{n})^2 = (1.88*2.2)^2

n = 17.1

Rounding up:

A sample of 18 is required.

3 0
2 years ago
If p(a)=a^3-6a^2+11a-9 and p(a)=-3,find the value of a?​
Colt1911 [192]
Correct because if you do the math correctly you solve it
8 0
1 year ago
PLEASE help me I need help
Alexxandr [17]

Answer:

D

Step-by-step explanation:

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7 0
3 years ago
Read 2 more answers
Suppose that surface σ is parameterized by r(u,v)=⟨ucos(3v),usin(3v),v⟩, 0≤u≤7 and 0≤v≤2π3 and f(x,y,z)=x2+y2+z2. Set up the sur
Bad White [126]

Looks like you have most of the details already, but you're missing one crucial piece.

\sigma is parameterized by

\vec r(u,v)=\langle u\cos3v,u\sin3v,v\rangle

for 0\le u\le7 and 0\le v\le\frac{2\pi}3, and a normal vector to this surface is

\dfrac{\partial\vec r}{\partial u}\times\dfrac{\partial\vec r}{\partial v}=\left\langle\sin3v,-\cos3v,3u\right\rangle

with norm

\left\|\dfrac{\partial\vec r}{\partial u}\times\dfrac{\partial\vec r}{\partial v}\right\|=\sqrt{\sin^23v+(-\cos3v)^2+(3u)^2}=\sqrt{9u^2+1}

So the integral of f(x,y,z)=x^2+y^2+z^2 is

\displaystyle\iint_\sigma f(x,y,z)\,\mathrm dA=\boxed{\int_0^{2\pi/3}\int_0^7(u^2+v^2)\sqrt{9u^2+1}\,\mathrm du\,\mathrm dv}

6 0
2 years ago
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