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Crazy boy [7]
2 years ago
6

Which best describes the range of the function #(x) = 2(3)x? O y>0 O y≥0 O y = 2 O y≥2

Mathematics
1 answer:
sdas [7]2 years ago
4 0

Answer:

The range of the function f(x) :  is y > 0.

The correct option is (A)

Step-by-step explanation:

The definition of range is the set of all possible values that the function will give when we give in the domain as input.

Given function is :

If we draw the graph for this, then we can see that the horizontal asymptote is 0.

So,  the range is real numbers higher than 0.

Hence, the range should be y > 0.

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Anna71 [15]
First thing to do is set up your equation:
45/x = 20/100
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3 years ago
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Find the common difference for the sequence shown: [1/5, 13/40, 9/20...)
bazaltina [42]
<h3>Answer:  1/8</h3>

Explanation:

Pick any term and subtract off the previous term to get the common difference.

So,

13/40 - 1/5 = 13/40 - 8/40 = (13-8)/40 = 5/40 = 1/8

Or

9/20 - 13/40 = 18/40 - 13/40 = (18-13)/40 = 5/40 = 1/8

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6 0
2 years ago
3 is subtracted from two-thirds of n
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A minus x plus b equals c
4 0
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Graphing linear inequalities digital escapes puzzle 4
Vadim26 [7]

Answer:

1 - F

2 - B

3 - H

4 - A

Step-by-step explanation:

1.

m = -2

b = 4

y < mx + b

y < -2x + 4

F

2.

m = 1

b = -2

y < mx + b

y < 1x -2

y < x - 2

B

3.

m = -4

y <= mx + b

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4.

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A is the only one that follows those rules

5 0
3 years ago
(3squared)squared x(10cubed)squared
kiruha [24]

Hii :))

\tt {(3 ^{2} )}^{2}  \times  {(10^{3}) }^{2}  \\ \tt  = (3 \times 3) ^{2}  \times  {(10 \times 10 \times 10)}^{2}  \\   \tt \: =  {9}^{2}  \times 1000 ^{2}  \\ \tt  = (9 \times 9) \times (1000 \times 1000) \\  = \tt \:  81  \times  1000000 \\  =  \boxed{\tt \:  81000000}

__________________

\overbrace{ \underbrace{ \mathfrak{ \: \infty  \:  Carry \: on \: Learning \:  \infty }}}

ᴛʜᴇᴇxᴛʀᴀᴛᴇʀᴇꜱᴛʀɪᴀʟ

3 0
2 years ago
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