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olga2289 [7]
3 years ago
12

Which system of equations are shown in each graph?

Mathematics
1 answer:
Allushta [10]3 years ago
8 0

Answer:

Option 1

Step-by-step explanation:

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(-2) 3 = plz help me I need help I need help I need help I need help
Degger [83]

Answer:

-6 is your answer.

Step-by-step explanation:

(-2)(-2)(-2)= -6

5 0
2 years ago
Read 2 more answers
Rabies is an often-fatal disease typically transmitted through the bite of an infected animal. The state of Florida has been rec
slega [8]

Answer:

a) 3.6

b) 1.897

c)0.0273

d) 0.9727

Step-by-step explanation:

Rabies has a rare occurrence and we can assume that events are independent. So, X the count of rabies cases reported in a given week is a Poisson random variable with μ=3.6.

a)

The mean of a Poisson random variable X is μ.

mean=E(X)=μ=3.6.

b)

The  standard deviation of a Poisson random variable X is √μ.

standard deviation=S.D(X)=√μ=√3.6=1.897.

c)

The probability for Poisson random variable X can be calculated as

P(X=x)=(e^-μ)(μ^x)/x!

where x=0,1,2,3,...

So,

P(no case of rabies)=P(X=0)=e^-3.6(3.6^0)/0!

P(no case of rabies)=P(X=0)=0.0273.

d)

P(at least one case of rabies)=P(X≥1)=1-P(X<1)=1-P(X=0)

P(at least one case of rabies)=1-0.0273=0.9727

8 0
2 years ago
A customer visiting the suit department of a certain store will purchase a suit with probability 0.22, a shirt with probability
Pachacha [2.7K]

Answer:

a. The probability that a customer purchase none of these items is 0.49

b. The probability that a customer purchase exactly 1 of these items would be of 0.28

Step-by-step explanation:

a. In order to calculate the probability that a customer purchase none of these items we would have to make the following:

let A represents suit

B represents shirt

C represents tie

P(A) = 0.22

P(B) = 0.30

P(C) = 0.28

P(A∩B) = 0.11

P(C∩B) = 0.10

P(A∩C) = 0.14

P(A∩B∩C) = 0.06

Therefore, the probability that a customer purchase none of these items we would have to calculate the following:

1 - P(A∪B∪C)

P(A∪B∪C) =P(A) + P(B) + P(C) − P(A ∩ B) − P(A ∩ C) − P(B ∩ C) + P(A ∩ B ∩ C)

= 0.22+0.28+0.30-0.11-0.10-0.14+0.06

= 0.51

Hence, 1 - P(A∪B∪C) = 1-0.51 = 0.49

The probability that a customer purchase none of these items is 0.49

b.To calculate the probability that a customer purchase exactly 1 of these items we would have to make the following calculation:

= P(A∪B∪C) - ( P(A∩B) +P(C∩B) +P(A∩C) - 2  P(A ∩ B ∩ C))

=0.51 -0.23 = 0.28

The probability that a customer purchase exactly 1 of these items would be of 0.28

6 0
3 years ago
The least common multiply of 2, 5, 6 and 9 is
Lady bird [3.3K]

Answer:

The LCM of 5, 6, and 9 is the product of all prime numbers on the left, i.e. LCM(5, 6, 9) by division method = 2 × 3 × 3 × 5 = 90.

8 0
2 years ago
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Starting at sea level a submarine rate to depth of -3/4 mile relative to sea level in 5 minutes. What was the submarine depth to
fgiga [73]
This you would have to do a proportion

5 0
3 years ago
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