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deff fn [24]
2 years ago
12

Solve the following proportion: 12.5/g = 17/6.8 . show your work.

Mathematics
1 answer:
lions [1.4K]2 years ago
6 0

12.5/g = 17/6.8

you cross multiply

12.5 * 6.8 = 85

17 * g = 17g

85 = 17g

divide each side by 17

g = 5

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2 years ago
When a distribution is mound-shaped symmetrical, what is the general relationship among the values of the mean, median, and mode
yuradex [85]

Answer:

The mean, median, and mode are approximately equal.

Step-by-step explanation:

The mean, median, and mode are <em>central tendency measures</em> in a distribution. That is, they are measures that correspond to a value that represents, roughly speaking, "the center" of the data distribution.

In the case of a <em>normal distribution</em>, these measures are located at the same point (i.e., mean = median = mode) and the values for this type of distribution are symmetrically distributed above and below the mean (mean = median = mode).

When a <em>distribution is not symmetrical</em>, we say it is <em>skewed</em>. The skewness is a measure of the <em>asymmetry</em> of the distribution. In this case, <em>the mean, median and mode are not the same</em>, and we have different possibilities as the mentioned in the question: the mean is less than the median and the mode (<em>negative skew</em>), or greater than them (<em>positive skew</em>), or approximately equal than the median but much greater than the mode (a variation of a <em>positive skew</em> case).  

In the case of the normal distribution, the skewness is 0 (zero).

Therefore, in the case of a <em>mound-shaped symmetrical distribution</em>, it resembles the <em>normal distribution</em> and, as a result, it has similar characteristics for the mean, the median, and the mode, that is, <em>they are all approximately equal</em>. So, <em>the </em><em>general</em><em> relationship among the values for these central tendency measures is that they are all approximately equal for mound-shaped symmetrical distributions, </em>considering they have similar characteristics of the <em>normal distribution</em>, which is also a mound-shaped symmetrical distribution (as well as the t-student distribution).

5 0
2 years ago
A hockey team's morning workout schedule consists of 15 minutes of warm-ups, 30 minutes of weight training, and 20 minutes of ae
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Hello! The ratio would be 15 minutes warm ups: 65 minutes total workout.

To simplify this: 3:13 ratio. (Divided 15 by 5 and 65 by 5)
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2 years ago
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Could someone please help me asap!! Pleasseeeee and thanks.
kherson [118]

Answer:

Step-by-step explanation:

a² - b² = (a + b) (a - b)

1)x² - 36 = x² - 6² = (x + 6)(x-6)

2) 4x² - 16 = 4x² - 4*4 = 4(x² - 4)

                = 4(x² -2²)

                = 4(x + 4)(x-4)

3) 9x² -1 = 3²x² - 1² = (3x)² - 1²

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8 0
3 years ago
How do you find the area of this figure?
loris [4]

Answer:

seis CM para 10 yd por eso

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