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Nitella [24]
3 years ago
14

The area of a rectangle gets reduced by 9 sq. units,if its length is reduced by 5 units and Breadth is increased by 3 units.If w

e increase the length by 3 units and Breadth 2 units ,the area increases by 67 units. Find the dimensions of rectangle. ​
Mathematics
1 answer:
Scilla [17]3 years ago
5 0

Let the length and breadth of the rectangle be x and y.

Area of rectangle is A = xy

Therefore, the new length will be = x-5

Therefore, the new breadth will be = y + 3

So new area will be xy-9

Now the new relation will be (x+3)(y+2)=xy+67

.

Cross – multiplication method–

\dfrac{x}{{{b_1}{c_2} - {b_2}{c_1}}} =\dfrac{y}{{{a_2}{c_1} - {c_2}{a_1}}} = \dfrac{1}{{{a_1}{b_2} - {a_2}{b_1}}} || x = \dfrac{{{b_1}{c_2} - {b_2}{c_1}}}{{{a_1} {b_2} - {a_2}{b_1}}} y = \dfrac{{{a_2}{c_1} - (c_2}{a_1}}}{{{a_1}{b_2}-{a_2}{b_1}}}\\

\Rightarrow \dfrac{x}{{305 - ( - 18)}} =\dfrac{y}{{ - 12 - ( - 183)}} = \dfrac{1}{{9 - 10)}}\\\

\Rightarrow \dfrac{x}{{323}} = \dfrac{y}{{171}} = \dfrac{1}{{19}} \\\Rightarrow x = 17, y = 9 \\

Therefore, the length is 17 and breadth is 9.

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Seventy-two percent of the light aircraft that disappear while in flight in a certain country are subsequently discovered. Of th
Anton [14]

Answer:

a) 0.105 = 10.5% probability that it will not be discovered if it has an emergency locator.

b) 0.522 = 52.2% probability that it will be discovered if it does not have an emergency locator.

c) 0.064 = 6.4% probability that 7 of them are discovered.

Step-by-step explanation:

For itens a and b, we use conditional probability.

For item c, we use the binomial distribution along with the conditional probability.

Conditional Probability

We use the conditional probability formula to solve this question. It is

P(B|A) = \frac{P(A \cap B)}{P(A)}

In which

P(B|A) is the probability of event B happening, given that A happened.

P(A \cap B) is the probability of both A and B happening.

P(A) is the probability of A happening.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

In which C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

And p is the probability of X happening.

a) If it has an emergency locator, what is the probability that it will not be discovered?

Event A: Has an emergency locator

Event B: Not located.

Probability of having an emergency locator:

66% of 72%(Are discovered).

20% of 100 - 72 = 28%(not discovered). So

P(A) = 0.66*0.72 + 0.2*0.28 = 0.5312

Probability of having an emergency locator and not being discovered:

20% of 28%. So

P(A cap B) = 0.2*0.28 = 0.056

Probability:

P(B|A) = \frac{P(A \cap B)}{P(A)} = \frac{0.056}{0.5312} = 0.105

0.105 = 10.5% probability that it will not be discovered if it has an emergency locator.

b) If it does not have an emergency locator, what is the probability that it will be discovered?

Probability of not having an emergency locator:

0.5312 of having. So

P(A) = 1 - 0.5312 = 0.4688

Probability of not having an emergency locator and being discovered:

34% of 72%. So

P(A \cap B) = 0.34*0.72 = 0.2448

Probability:

P(B|A) = \frac{P(A \cap B)}{P(A)} = \frac{0.2448}{0.4688} = 0.522

0.522 = 52.2% probability that it will be discovered if it does not have an emergency locator.

c) If we consider 10 light aircraft that disappeared in flight with an emergency recorder, what is the probability that 7 of them are discovered?

p is the probability of being discovered with the emergency recorder:

0.5312 probability of having the emergency recorder.

Probability of having the emergency recorder and being located:

66% of 72%. So

P(A \cap B) = 0.66*0.72 = 0.4752

Probability of being discovered, given that it has the emergency recorder:

p = P(B|A) = \frac{P(A \cap B)}{P(A)} = \frac{0.4752}{0.5312} = 0.8946

This question asks for P(X = 7) when n = 10. So

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 7) = C_{10,7}.(0.8946)^{7}.(0.1054)^{3} = 0.064

0.064 = 6.4% probability that 7 of them are discovered.

8 0
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Wittaler [7]
(40 min)/(5 mi) = (time)/(7 mi) . . . . . the rates are the same
(7/5)*(40 min) = time = 56 min

At the same rate, it would take Petra 56 minutes to jog 7 miles.
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4 years ago
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There are 714 boys in that school, you can cross multiply and divide to find the answer, if you wanna check. The way I wrote it was x (boys) / 1309 = 6/11.
3 0
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She will earn $2,000 fees for the 4 cars that she sold.
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3 years ago
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