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Setler79 [48]
3 years ago
6

The point at the beginning of a ray is called what?

Mathematics
2 answers:
Ulleksa [173]3 years ago
7 0
An endpoint is the point a ray starts from
anyanavicka [17]3 years ago
6 0
It's called the endpoint lol
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It’s 280 I believe...
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Explain how to solve the equation and how to check the solution. 40 = 8y
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Answer:

U already know the answer, then why ask?? I'll explain it once again, tho :)

Step-by-step explanation:

40 = 8y

40 ÷ 8= y

<u>5 = </u><u>y</u>

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Identify the inequality that corresponds to the graph below. Choose all that apply.
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The answer is a because it is open circle
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RS bisects QRT, mangleQRS = (3x + 8), and mangleSRT = (5x − 4).
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3 years ago
USE THE ATTACHED IMAGE BELOW TO HELP DO MY HOMEWORK PLEASE<br> !!!!
BartSMP [9]

Part A

Sue

A = P*(1+r/n)^(n*t) is the compound interest formula

A = 2300*(1+0.024/1)^(1*3)

A = 2469.6061952

A = 2469.61

A - P = 2469.61-2300 = 169.61

<h3>Sue gets 169.61 pounds in interest</h3>

-----------

Bill

A = P*(1+r/n)^(n*t)

A = 1800*(1+0.034/1)^(1*3)

A = 1989.9131472

A = 1989.91

A-P = 1989.91-1800 = 189.91

<h3>Bill earns 189.91 pounds in interest</h3>

Bill has earned more in interest.

=====================================================

Part B

By year 2, Bill has 1924.48 pounds in his account based on the work shown below

A = P*(1+r/n)^(n*t)

A = 1800*(1+0.034/1)^(1*2)

A = 1924.4808

A = 1924.48

This amount is the new deposit, so to speak, when we change the interest rate. Now r = 0.034 changes to r = 0.04. We only go for one year so t = 1

A = P*(1+r/n)^(n*t)

A = 1924.48*(1+0.04/1)^(1*1)

A = 2001.4592

A = 2001.46

Bill has 2001.46 pounds in his account after 3 years if the interest rate for the 1234 account changes to 4% in the third year.

Now subtract off the original amount Bill deposited to get

2001.46-1800 = 201.46

For this scenario, Bill earns 201.46 pounds in interest.

Therefore, Bill has earned the most interest for both cases of the interest rate staying at 3.4% or changing to 4% for that third year.

<h3>Answer: Bill</h3>
8 0
3 years ago
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