10.1666666667
Hope it helps
Temporarily subdivide the given area into two parts: a large rectangle and a parallelogram. Find the areas of these two shapes separately and then combine them for the total area of the figure.
By counting squares on the graph, we see that the longest side of the rectangle is the hypotenuse of a triangle whose legs are 8 and 2. Applying the Pyth. Thm., we find that this length is √(8^2+2^2), or √68. Similarly, we find the the width of this rectangle is √(17). Thus, the area of the rectangle is √(17*68), or 34 square units.
This leaves the area of the parallelogram to be found. The length of one of the longer sides of the parallelogram is 6 and the width of the parallelogram is 1. Thus, the area of the parallelogram is A = 6(1) = 6 square units.
The total area of the given figure is then 34+6, or 40, square units.
The <u>correct answer</u> is:
It is not a very strong fit.
Explanation:
The r-value, or correlation coefficient, tells us how closely our model fits the data.
The r-values range from -1 to 1. -1 is a perfect fit of a decreasing model; 1 is a perfect fit of an increasing model. 0 is no fit at all.
Since our r-value is 0.29, this is much closer to 0 than it is to 1 or -1; this means it is not a very strong fit.
The triangles ABC and EDF are congruent, meaning they have the same side lengths and angles measures.
The measure of DF, as both triangles are congruent, is equal to the measure of BC.
We can calculate the length of BC using the distance formula:
![\begin{gathered} D=\sqrt[]{(x_c-x_b)^2+(y_c-y_b_{})^2} \\ D=\sqrt[]{(2-2)^2+(-1-4)^2} \\ D=\sqrt[]{0^2+(-5)^2} \\ D=\sqrt[]{(-5)^2} \\ D=|-5| \\ D=5 \end{gathered}](https://tex.z-dn.net/?f=%5Cbegin%7Bgathered%7D%20D%3D%5Csqrt%5B%5D%7B%28x_c-x_b%29%5E2%2B%28y_c-y_b_%7B%7D%29%5E2%7D%20%5C%5C%20D%3D%5Csqrt%5B%5D%7B%282-2%29%5E2%2B%28-1-4%29%5E2%7D%20%5C%5C%20D%3D%5Csqrt%5B%5D%7B0%5E2%2B%28-5%29%5E2%7D%20%5C%5C%20D%3D%5Csqrt%5B%5D%7B%28-5%29%5E2%7D%20%5C%5C%20D%3D%7C-5%7C%20%5C%5C%20D%3D5%20%5Cend%7Bgathered%7D)
As BC is congruent with DF and BC=5, the length of DF is 5 units.
Step-by-step explanation:
-4 (-x + 2) = 2 (3x - 7)
2x-4=3x-7
x=3
