Answer:
Problem B: x = 12; m<EFG = 48
Problem C: m<G = 60; m<J = 120
Step-by-step explanation:
Problem B.
Angles EFG and IFH are vertical angles, so they are congruent.
m<EFG = m<IFH
4x = 48
x = 12
m<EFG = m<IFH = 48
Problem C.
One angle is marked a right angle, so its measure is 90 deg.
The next angle counterclockwise is marked 30 deg.
Add these two measures together, and you get 120 deg.
<J is vertical with the angle whose measure is 120 deg, so m<J = 120 deg.
Angles G and J from a linear pair, so they are supplementary, and the sum of their measures is 180 deg.
m<G = 180 - 120 = 60
Answer:
900 degrees
Step-by-step explanation:
The sum of the interior angles of a polygon can be found by
(n-2)*180 where n is the number of sides
This figure has 7 sides
(7-2)*180
5*180
900
Y= 3(3)–2(3)2+5(3)3
y= 9–2*3*2+5*9
y=9–12+5*9
y=9–12+45
y=42
25 because the first square is a 3 by 3= 9 and the other one is 36 which is 6 by 6 and the last one is 4 by 4 so the last one is 5 by 5 or 25
Y = 4 x + 3
<span>y = 4 x + 3/2
</span>no solution :) hope this helps
