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Talja [164]
3 years ago
6

On a string of red and blue lights, the red lights blink everyb3 seconds, and the blue lights blink every 5 seconds. How many ti

mes will they blink at the same time in one minute?
Mathematics
1 answer:
yuradex [85]3 years ago
5 0
When will they blink together?
what is the smallest number they both mutiply to
3*5=15
so every 15 seconds
so at 15, 30, 45, 60 seconds
so 4 times if you count the time exactly at 1 minute
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Is -8 = 8
madam [21]
No solution

The answer is D
5 0
2 years ago
Make a ten or a hundred to add mentally 339+123
lianna [129]
9+3=12
30+20=50
300+100=400
Then add.
12+50+400=462
<span>So 339+123=462</span>
5 0
3 years ago
Evaluate................
wolverine [178]

Answer:

h(8q²-2q) = 56q² -10q

k(2q²+3q) = 16q² +31q

Step-by-step explanation:

1. Replace x in the function definition with the function's argument, then simplify.

h(x) = 7x +4q

h(8q² -2q) = 7(8q² -2q) +4q = 56q² -14q +4q = 56q² -10q

__

2. Same as the first problem.

k(x) = 8x +7q

k(2q² +3q) = 8(2q² +3q) +7q = 16q² +24q +7q = 16q² +31q

_____

Comment on the problem

In each case, the function definition says the function is not a function of q; it is only a function of x. It is h(x), not h(x, q). Thus the "q" in the function definition should be considered to be a literal not to be affected by any value x may have. It could be considered another way to write z, for example. In that case, the function would evaluate to ...

h(8q² -2q) = 56q² -14q +4z

and replacing q with some value (say, 2) would give 196+4z, a value that still has z as a separate entity.

In short, I believe the offered answers are misleading with respect to how you would treat function definitions in the real world.

7 0
3 years ago
If a polygon is a square, then it is also a rectangle.<br><br><br> True<br><br> or <br><br> False
Art [367]

Answer:

true

Step-by-step explanation:

a square will always be a rectangle but a rectangle will not always be a square.

7 0
3 years ago
Read 2 more answers
Use substitution method <br>3x +4y+175x-2y=11​
Viefleur [7K]

3x +4y+175x-2y=11

4y-2y+175x+3x=11

2y+178x=11

2y=11-178x

y=\frac{11-178x}{2}

y=-89x+\frac{11}{2}

178x=-2y+11

x=\frac{-2y+11}{178}

x=\frac{-1}{89} y+\frac{11}{178}

4 0
3 years ago
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