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denis23 [38]
4 years ago
10

What method will speed up a chemical reaction?

Chemistry
1 answer:
Brrunno [24]4 years ago
6 0
I think it is A correct me if i am wrong hope this helps
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How is synthesis and decomposition reaction related to each other???
Anit [1.1K]
They are kind of opposite processes. Chemical synthesis is execution of chemical reactions to make products. Like you take two substances, you put them together, they react and you have new a substance. For example. 2Na+{ Cl }_{ 2 }\rightarrow 2NaCl here Sodium and Chlorine react to make a new substance which is Sodium Chloride.

Chemical decomposition is process of seperating a substance to different substances. There is a substance by a reaction this substance becomes two substances, Like : XY -> X+Y For example : 2{ H }_{ 2 }O(l)\quad \rightarrow 2{ H }_{ 2 }+{ O }_{ 2 }
8 0
3 years ago
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Helium decays to form lithium.
hjlf

Answer:

Natural nuclear disintegration.

Explanation:

This is because it cannot be managed, like it needs no energy particle yo occur, so its natural for helium to decay.

But it is nuclear because helium decays to release an energy particle (Beta particle).

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3 years ago
When you are doing an experiment that will have multiple trials, how do you handle averages?
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The answer is B. <span>The individual trials and the averages should each have their own columns in the data table.

In an experiment, you want to be able to see all of the data, so you should always include the data from each individual trial; however, it's important to have a separate column for averages, so you are able to compare all of the data.

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5 0
4 years ago
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You need to make an aqueous solution of 0.215 M aluminum bromide for an experiment in lab, using a 300 mL volumetric flask. How
Karo-lina-s [1.5K]

Answer:

We have to add 17.2 grams of aluminium bromide

Explanation:

Step 1: Data given

Molarity of the aluminum bromide solution = 0.215 M

Volume = 300 mL = 0.300 L

Molar mass aluminium bromide = 266.69 g/mol

Step 2: Calculate moles Aluminium bromide

moles AlBr3 = volume * molarity

Moles AlBr3 = 0.300 L * 0.215 M

Moles AlBR3 = 0.0645 moles

Step 3: Calculate mass aluminium bromide

Mass aluminium bromide = moles AlBr3 * molar mass AlBr3

Mass aluminium bromide = 0.0645 moles * 266.69 g/mol

Mass aluminium bromide = 17.2 grams

We have to add 17.2 grams of aluminium bromide

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3 years ago
Consider the reaction below:
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What are <span>stoichiometry equations?</span>
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3 years ago
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