Question

In a closed container with a fixed volume, when the temperature of a gas doubles, the pressure of the gas is?

Answer 1

Answer:

The pressure of the gas is:

Doubled

Explanation:

Byole's Law  = Pressure of fixed amount of gas is inversely proportional to Volume at constant temperature.

PV = k = constant

P1V1 = P2V2

Charle's Law: The volume of ideal gas at fixed pressure is directly proportional to Pressure.

V/T = constant

V1/T1 = V2/T2

On combinig the charles and byole's law , we get:

$\frac{P_{1}V_{1}}{T_{1}}=\frac{P_{2}V_{2}}{T_{2}}$

Now , According to question :

V2 = V1

T2 = 2(T1)

We have to find the relation between the pressure :

insert the value in the equation

$\frac{P_{1}V_{1}}{T_{1}}=\frac{P_{2}V_{2}}{T_{2}}$

$\frac{P_{1}V_{1}}{T_{1}}=\frac{P_{2}V_{1}}{2T_{1}}$

V1 and V1 & T1 and T1 cancels each other,

So we get

P2 = 2 P1

So the new pressure is double of the original pressure