Question

PLEASE HELP ME ANSWER THESE QUESTIONS!

Answer 1

Answer:

1. 0.35 moles NaOH

2. $5.10x10^{-4}$ moles $H_2SO_4$

3. 505.4 g Pb

4. 1.46 g HCl (if that is wrong it's 1.5 g HCl due to sig figs)

5. $3.01x10^{23}$ atoms of Ag

6. $2x10^{-10}$ atoms of Cu

Explanation:

1. The mass of NaOH is 40g. 22.99(Na)+16(O)+1.01(H)=40 g

14 g NaOH *$\frac{1 mol NaOH}{40 g NaOH}$ = 0.35 moles of NaOH

2. Mass of $H_{2} SO_{4} = 2(1.01)+32.06+4(16) = 98.08$

0.05 g $H_2SO_4$ ×$\frac{1 mol H_2SO_4}{98.08g H_2SO_4} = 5.10 x10^{-4}$

3. mass of Pb = 106.4 g

4.75 moles Pb×$\frac{106.4 g Pb}{1 mol Pb} =505.4 g Pb$

4. mass of HCl = 1.01 +35.45 = 36.36 g

0.04 mol HCl x $\frac{36.46 g HCl}{1 mol HCl} = 1.456 = 1.5$

5. 5.00 mol Ag x$\frac{6.022x10^{23} atoms }{1mol Ag} = 3.01x10^{24} atoms$

6. $3x10^{-10} moles$ Cu x$\frac{6.022x10^{23} atoms}{1 mol Cu} = 1.8668x10^{14}= 2x10^{14}$ atoms of Cu