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Oksanka [162]
2 years ago
6

Write an equivalent expression. 2 + 4(c + 7)

Mathematics
1 answer:
Alex777 [14]2 years ago
3 0
2 + 4 (c + 7)
2 + 4c + 28
combine liked terms
4c + 30

Answer:
B) 30 + 4c
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The square of a number is 12 less than 7 times the number. What is the number?
hjlf

<u><em>Answer:</em></u>

The number is either 3 or 4


<u><em>Explanation:</em></u>

Assume that the number we are looking for is x

The square of the number would be x²

7 times the number would be 7x


<u>We are given that:</u>

square of the number (x²) is 12 less than 7 times the number (7x)


<u>Translating this into an equation, we would have:</u>

x² = 7x - 12


<u>Rearranging the quadratic equation:</u>

x² - 7x + 12 = 0


<u>Now, we factor the equation:</u>

(x-4)(x-3) = 0


<u>This means that:</u>

either x-4 = 0 ..................> x = 4

or x-3 = 0 ........................> x = 3


<u>Let's check if any of the solutions is an extrovert:</u>

For x = 3 .............> (3)² = 7(3) - 12 .........> 9 = 21 - 12 .......> 9 = 9 .......> not extrovert

For x = 4 .............> (4)² = 7(4) - 12 .........> 16 = 28 - 12 .....> 16 = 16 ....> not extrovert


Since we have no restrictions on the number, therefore, both solutions would be accepted


Hope this helps :)


7 0
3 years ago
Get Geordi Through the Door geometry worksheet
Murljashka [212]

Answer:

what does that even mean'

Step-by-step explanation:

3 0
3 years ago
Write the trigonometric expression in terms of sine and cosine, and then simplify.
katrin2010 [14]
Hello,

tan t /(sec t -cos t)= sin t/(cos t *(1/cos t -cos t))
=sin t/(cos t*(1-cos ²t)/cos t))
=sin t/sin² t=1/sin t [or=cosec t.]

3 0
3 years ago
<img src="https://tex.z-dn.net/?f=x%20%7B%7D%5E%7B2%7D%20%20-%202ax%20%2B%202%28a%20%7B%7D%5E%7B2%7D%20%20-%206%29%20%3D%200" id
pentagon [3]

answer

- {4a}^{2}  + 48

5 0
3 years ago
Find the vertical and horizontal asympotote for (×-2) (×+3)/ (2×+2)
nekit [7.7K]

\bf \cfrac{(x-2)(x+3)}{2x+2}\implies \cfrac{x^2+x-6}{2x+2}~~ \begin{array}{llll} \leftarrow \textit{2nd degree polynomial}\\ \leftarrow \textit{1st degree polynomial} \end{array} \\\\[-0.35em] ~\dotfill\\\\ \stackrel{\textit{vertical asymptote}}{2x+2=0}\implies 2x=-2\implies x=-\cfrac{2}{2}\implies x=-1


when the degree of the numerator is greater than the denominator's, then it has no horizontal asymptotes.


quick note:

when the degree of the numerator is 1 higher than the degree of the denominator, then it has an slant-asymptote, so this one has a slant-asymptote.

6 0
3 years ago
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