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2 years ago

Write an equivalent expression. 2 + 4(c + 7)

Mathematics

1 answer:

Alex777 [14]2 years ago

3 0

2 + 4 (c + 7)
2 + 4c + 28
combine liked terms
4c + 30

Answer:
B) 30 + 4c

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Let Y be a random variable with a density function given by

Neporo4naja [7]

From the given density function we find the distribution function,

$F_Y(y)=P(Y\le y)=\displaystyle\int_{-\infty}^y f_Y(t)\,\mathrm dt=\begin{cases}0&\text{for }y$

(a)

$F_{U_1}(u_1)=P(U_1\le u_1)=P(3Y\le u_1)=P\left(Y\le\dfrac{u_1}3\right)=F_Y\left(\dfrac{u_1}3\right)$

$\implies F_{U_1}(u_1)=\begin{cases}0&\text{for }u_1$

$\implies f_{U_1}(u_1)=\begin{cases}\frac{{u_1}^2}{18}&\text{for }-3\le u_1\le3\\0&\text{otherwise}\end{cases}$

(b)

$F_{U_2}(u_2)=P(3-Y\le u_2)=P(Y\ge3-u_2)=1-P(Y$

$\implies F_{U_2}(u_2)=\begin{cases}0&\text{for }u_2$

$\implies f_{U_2}(u_2)=\begin{cases}\frac32(u_2-3)^2&\text{for }2\le u_2\le4\\0&\text{otherwise}\end{cases}$

(c)

$F_{U_3}(u_3)=P(Y^2\le u_3)=P(-\sqrt{u_3}\le Y\le\sqrt{u_3})=F_Y(\sqrt{u_3})-F_y(\sqrt{u_3})$

$\implies F_{U_3}(u_3)=\begin{cases}0&\text{for }u_3$

$\implies f_{U_3}(u_3}=\begin{cases}\frac32\sqrt u&\text{for }0\le u\le1\\0&\text{otherwise}\end{cases}$

5 0

2 years ago

What is the inequality of 6x-4<8?

Kobotan [32]

6x - 4 < 8

Add 4 to both sides:
6x < 12

Divide both sides by 6:
x < 2

Answer: x < 2

7 0

3 years ago

How do I do this help pt2

matrenka [14]

What is the question is the o

8 0

2 years ago

Read 2 more answers

What are the coordinates of the point on the directed line segment from (1,-5) to

Black_prince [1.1K]

Answer:

Q (2.5, -4)

Step-by-step explanation:

Let A (1, -5), C = (10, 1), find Q (x, y), so that AQ:QC = 1:5

AQ = (x - 1, y + 5)

QC = (10 - x, 1 - y)

AQ:QC = 1:5

so 5*AQ = QC

5(x - 1) = (10 - x)

5(y + 5) = 1 - y

Solve them:

5x - 5 = 10 - x

6x = 15

x = 15/6 = 2.5

5y + 25 = 1 - y

6y = -24

y = -24/6 = -4

Then answer is Q (2.5, -4)

6 0

2 years ago

Your friend incorrectly factors the expression 15x — 20xy as 5x(3— 4xy

nika2105 [10]

Answer:

no 15x — 20xy as 5x(3— 4xy is not correct

Step-by-step explanation:

15x — 20xy ≠ 5x(3— 4xy)

there are not equal because 5x(3 - 4xy) =

when you simplify the bracket, you will have

15x - 20x²y

6 0

3 years ago