15x=-32-14y<br> 9x=-64+14y

Helppp

yulyashka [42]

Answer:

Step-by-step explanation:

4 0

3 years ago

Read 2 more answers

20 points and brainliest answer for correct answer. Photo above. Due by 9:45 today! Hi

SSSSS [86.1K]

Answer:

146 square meters

Step-by-step explanation:

We can split the figure into a 6 by 15 rectangle and a parallelogram (8 base, 7 height).

The area of the rectangle is 6•15=90
The area of the parallelogram is 8•7=56
90+56=146

7 0

3 years ago

2r = 72 please help me

noname [10]

you divide 72 by 2 to get r by itself and get 36

so r=36

6 0

3 years ago

Read 2 more answers

A tire manufacturer is considering a newly designed tread pattern for its all-weather tires. Tests have indicated that these tir

Nataly_w [17]

Answer:

With outlier (102)

$t=\frac{126.2-125}{\frac{9.138}{\sqrt{10}}}=0.415$

$p_v =P(t_{9}>0.415)=0.344$

If we compare the p value and a significance level assumed $\alpha=0.05$ we see that $p_v>\alpha$ so we can conclude that we have enough evidence to FAIL to reject the null hypothesis, so we can conclude that the true mean is not significantly higher than 125 feet at 5% of significance.

Without outlier (102)

$t=\frac{128.89-125}{\frac{3.551}{\sqrt{9}}}=3.285$

$p_v =P(t_{8}>3.285)=0.0056$

And we conclude that we reject the null hypothesis since $p_v$ . So the final conclusion would be not use the method since the value of 102 observed can be a potential outlier, removing this value we see that we reject the null hypothesis and we have a significant result that the true mean is higher than 125.

Step-by-step explanation:

Previous concepts and data given

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

Data: 129, 128, 130, 132, 135, 123, 102, 125, 128, 130

We can calculate the mean with the following formulas:

$\bar X =\frac{\sum_{i=1}^n X_i}{n}$

$s=\sqrt{\frac{\sum_{i=1}^n (X_i -\bar X)^2}{n-1}}$

$\bar X=126.2$ represent the sample mean

$s=9.138$ represent the sample standard deviation

n=10 represent the sample selected

$\alpha$ significance level

State the null and alternative hypotheses.

We need to conduct a hypothesis in order to check if the mean is significantly higher than 125, the system of hypothesis would be:

Null hypothesis: $\mu \leq 125$

Alternative hypothesis: $\mu > 125$

If we analyze the size for the sample is < 30 and we don't know the population deviation so is better apply a t test to compare the actual mean to the reference value, and the statistic is given by:

$t=\frac{\bar X-\mu_o}{\frac{s}{\sqrt{n}}}$ (1)

t-test: "Is used to compare group means. Is one of the most common tests and is used to determine if the mean is (higher, less or not equal) to an specified value".

Calculate the statistic

We can replace in formula (1) the info given like this:

$t=\frac{126.2-125}{\frac{9.138}{\sqrt{10}}}=0.415$

P-value

First we need to calculate the degrees of freedom given by:

$df=n-1=10-1= 9$

Then since is a right tailed sided test the p value would be:

$p_v =P(t_{9}>0.415)=0.344$

Conclusion

If we compare the p value and a significance level assumed $\alpha=0.05$ we see that $p_v>\alpha$ so we can conclude that we have enough evidence to FAIL to reject the null hypothesis, so we can conclude that the true mean is not significantly higher than 125 feet at 5% of significance.

Using all the data we see that we don;t have enough info to conclude that the true mean is higher than 125, but if we see careful 9 of the 10 values are over the limit of 125 feet. And if we repeat the procedure with the outlier of 102. We got this:

$\bar X=128.89$ represent the sample mean

$s=3.551$ represent the sample standard deviation

$t=\frac{128.89-125}{\frac{3.551}{\sqrt{9}}}=3.285$

First we need to calculate the degrees of freedom given by:

$df=n-1=9-1= 8$

Then since is a right tailed sided test the p value would be:

$p_v =P(t_{8}>3.285)=0.0056$

And we conclude that we reject the null hypothesis since $p_v$ . So the final conclusion would be not use the method since the value of 102 observed can be a potential outlier removing this value we see that we reject the null hypothesis and we have a significant result that the true mean is higher than 125.

8 0

3 years ago

How do i Evaluate In 7. ?

Pachacha [2.7K]

Answer:

(b) 1.95

Step-by-step explanation:

One of the easiest ways to evaluate an arithmetic expression of almost any kind is to type it into an on-line calculator. Many times, typing it into a search box is equivalent.

<h3>Application</h3>

See the attachment for the search box input (at top) and the result. This calculator has the benefit that it <em>always follows the Order of Operations</em> when evaluating an expression. (Not all calculators do.)

ln(7) ≈ 1.95

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<em>Additional comment</em>

If your math course is asking you to evaluate such expressions, you have probably been provided a calculator to use, or given the requirements for a calculator suitable for use in the course.

There are some very nice calculator apps for phone and tablet. Many phones and tablets already come with built-in calculator apps. For the purpose here, you need a "scientific" or "graphing" calculator. A 4-function calculator will not do.

As with any tool, it is always a good idea to read the manual for your calculator and work through any example problems.

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Years ago, handheld calculators were not available, and most desktop calculators were only capable of the basic four arithmetic functions. Finding a logarithm required use of a table of logarithms. Such tables were published in mathematical handbooks, and extracts of those often appeared as appendices in math textbooks used in school.

3 0

2 years ago

15x=-32-14y 9x=-64+14y