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A 13-ounce box of cereal sells for $3.25. An 18-ounce box of cereal sells for $3.60. Which statement describes the difference in
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Answer:
Step-by-step explanation:
Hi there!
We are given the following equation:
x+6y=-6
And we want to convert it into slope-intercept form
Slope-intercept form is known as y=mx+b, where m is the slope and b is the y intercept
The equation is currently in standard form, which is ax+by=c, where a, b, and c are integer coefficients
Notice how in standard form, both the terms that contain x and y are on one side, but in slope-intercept form, y is by itself on one side
So essentially, in order to convert from standard form to slope-intercept form, we need to solve for y
Here is our equation again:
x+6y=-6
Start by subtracting x from both sides
x+6y=-6
-x -x
_______________
6y=-x-6
Now divide both sides by 6
We can simplify the fractions to become:
Hope this helps!
See more on converting from standard to slope-intercept form here: brainly.com/question/26579052
Answer:
0.8926 = 89.26% probability that the mean weight of the sample of horses would differ from the population mean by less than 15lbs if 31 horses are sampled at random from the stable
Step-by-step explanation:
To solve this question, we need to understand the normal probability distribution and the central limit theorem.
Normal probability distribution
Problems of normally distributed samples are solved using the z-score formula.
In a set with mean and standard deviation
, the zscore of a measure X is given by:
The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.
Central Limit Theorem
The Central Limit Theorem estabilishes that, for a normally distributed random variable X, with mean and standard deviation
, the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean
and standard deviation
.
For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.
In this problem, we have that:
What is the probability that the mean weight of the sample of horses would differ from the population mean by less than 15lbs if 31 horses are sampled at random from the stable?
pvalue of Z when X = 975 + 15 = 990 subtracted by the pvalue of Z when X = 975 - 15 = 960. So
X = 990
By the Central Limit Theorem
has a pvalue of 0.9463
X = 960
has a pvalue of 0.0537
0.9463 - 0.0537 = 0.8926
0.8926 = 89.26% probability that the mean weight of the sample of horses would differ from the population mean by less than 15lbs if 31 horses are sampled at random from the stable