Answer:
4r ^2 +9r + 12
Step-by-step explanation:
Hope this helps! :)
To find the maximum or minimum value of a function, we can find the derivative of the function, set it equal to 0, and solve for the critical points.
H'(t) = -32t + 64
Now find the critical numbers:
-32t + 64 = 0
-32t = -64
t = 2 seconds
Since H(t) has a negative leading coefficient, we know that it opens downward. This means that the critical point is a maximum value rather than a minimum. If we weren't sure, we could check by plugging in a value for t slightly less and slighter greater than t=2 into H'(t):
H'(1) = 32
H'(3) = -32
As you can see, the rate of change of the object's height goes from increasing to decreasing, meaning the critical point at t=2 is a maximum.
To find the height, plug t=2 into H(t):
H(2) = -16(2)^2 +64(2) + 30 = 94
The answer is 94 ft at 2 sec.
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Step(1)
To find q(a) we just need to put a instead of x in q(x) function.
Let's do it...
Multiply sides by -2 :
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Step (2)
To find q(a+1) we just need to put a+1 instead of x in q(x) function.
Let's do it...
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Step (3)
And we're done.
Thanks for watching buddy good luck.
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10/10 in 1 whole and 1/100 in one whole
