The mean is defined as the

1 answer:

7 0

Is the average of the numbers: a calculated "central" value of a set of numbers. To calculate: Just add up all the numbers, then divide by how many numbers there are.

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A food truck sells tacos for 75¢ apiece. The truck operator earned $240 last night.

kykrilka [37]

Answer:

he sold 320 tacos

Step-by-step explanation:

240÷.75=320

5 0

3 years ago

I need help with these three equations 3x - 2 = x + 10 X+4=19-2x 8z - 20 =z +15

lapo4ka [179]

Answer:

1st answer is 6, 2nd is 5, 3rd is 5

Step-by-step explanation:

3x-2=x+10

3x-x=10+2

2x=12

x=12÷2

x=6

x+4=19-2x

x+2x=19-4

3x=15

x=15÷3

x=5

8z-20=z+15

8z-z=15+20

7z=35

z=35÷7

z=5

plzz mark me as brainliest

4 0

3 years ago

Read 2 more answers

Find the critical numbers of the function. (Enter your answers as a comma-separated list. If an answer does not exist, enter DNE

EleoNora [17]

Answer:

0, 10

Step-by-step explanation:

The given function is:

$g(y) = \frac{y-5}{y^2-3y+15}$

According to the quotient rule:

$d(\frac{f(y)}{h(y)}) = \frac{f(y)*h'(y)-h(y)*f'(y)}{h^2(y)}$

Applying the quotient rule:

$g(y) = \frac{y-5}{y^2-3y+15}\\g'(y)=\frac{(y-5)*(2y-3)-(y^2-3y+15)*(1)}{(y^2-3y+15)^2}$

The values for which g'(y) are zero are the critical points:

$g'(y)=0=\frac{(y-5)*(2y-3)-(y^2-3y+15)*(1)}{(y^2-3y+15)^2}\\(y-5)*(2y-3)-(y^2-3y+15)=0\\2y^2-3y-10y+15-y^2+3y-15\\y^2-10y=0\\y=\frac{10\pm \sqrt 100}{2}\\y_1=\frac{10-10}{2}= 0\\y_2=\frac{10+10}{2}=10$