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Ad libitum [116K]
3 years ago
10

Question 1 What is the dashed part of the figure below?

Mathematics
2 answers:
Afina-wow [57]3 years ago
8 0
Where is the figure at?
photoshop1234 [79]3 years ago
4 0

Answer:

The answer is line segment.

Step-by-step explanation:

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Select the correct location on the graph.
pochemuha

Answer:

it's d it makes alot of sense and ik it's right

3 0
2 years ago
-w + 4(w+3) = -12<br><br> Please help
Ivahew [28]
Let's solve your equation step-by-step.<span><span><span>−w</span>+<span>4<span>(<span>w+3</span>)</span></span></span>=<span>−12</span></span>Step 1: Simplify both sides of the equation.<span><span><span>−w</span>+<span>4<span>(<span>w+3</span>)</span></span></span>=<span>−12</span></span><span>Simplify: (Show steps)</span><span><span><span>3w</span>+12</span>=<span>−12</span></span>Step 2: Subtract 12 from both sides.<span><span><span><span>3w</span>+12</span>−12</span>=<span><span>−12</span>−12</span></span><span><span>3w</span>=<span>−24</span></span>Step 3: Divide both sides by 3.<span><span><span>3w</span>3</span>=<span><span>−24</span>3</span></span><span>w=<span>−8</span></span>Answer:<span>w=<span>−<span>8</span></span></span>
4 0
2 years ago
Read 2 more answers
Andy was scuba diving while his friend Ramon was climbing a mountain. If Andy was at an elevation of -100 feet, and Ramon was at
Dafna1 [17]

Answer:

1075 feet

Step-by-step explanation:

5 0
3 years ago
Complete the statement below that show y=8^2+32x+17 being converted to vertex form
OverLord2011 [107]
\left[y \right] = \left[ 81+32\,x\right][y]=[81+32x] being converted to vertex form
7 0
3 years ago
In a recent​ year, an author wrote 169 checks. Use the Poisson distribution to find the probability​ that, on a randomly selecte
grigory [225]
We should first calculate the average number of checks he wrote per day.  To do that, divide 169 by 365 (the number of days in a year) and you get (rounded) 0.463.  This will be λ in our Poisson distribution.  Our formula is
P(X=k)= \frac{ \lambda ^{k}-e^{-\lambda} }{k!}.  We want to evaluate this formula for X≥1, so first we must evaluate our case at k=0.  
P(X=0)= \frac{0.463 ^{0}-e ^{-0.463} }{0!} \\ = \frac{1-e ^{-0.463} }{1} =0.3706
To find P(X≥1), we find 1-P(X<1).  Since the author cannot write a negative number of checks, this means we are finding 1-P(X=0).  Therefore we have 1-0.3706=0.6294.
There is a 63% chance that the author will write a check on any given day in the year.<em />
8 0
2 years ago
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