Answer:
Proved
Step-by-step explanation:
Given: EC || AC, DB || AC, ∠A = ∠F
Prove: ΔMDF ∼ ΔNCA
Solution
See diagram attached to the solution to better understand the following workings.
Redrawing ΔMDF or rotating to be facing the same direction.
EC is parallel to AC
DB parallel to AC
Using similar triangle theorem:
If ΔMDF ∼ ΔNCA
Ratio of Corresponding sides would be equal
(adjacent of ΔMDF)/(adjacent of ΔNCA) = (Opposite of ΔMDF)/(opposite of ΔNCA) = (hypotenuse of ΔMDF)/(hypotenuse of ΔNCA)
DF/ CA = MD/NC = FM/AN
∠A = ∠F
∠M = ∠N
∠D = ∠C
Since the ratio of Corresponding sides and angle are equal, ΔMDF is similar to ΔNCA.
ΔMDF ∼ ΔNCA
All your answers look good!
Answer: See explanation
Step-by-step explanation:
Total water fetched = 24 pints.
Jill drank a tenth of this. This will be:
= 1/10 × 24
= 2.4 pints
Jack drank a quarter. This will be:
= 1/4 × 24 = 6.
They gave three eighths to dame Dob . Thus will be:
= 3/8 × 24
= 9
They gave a fifth to jill's mother. This will be:
= 1/5 × 24.
= 4.80
Amount that'll be left over will be:
= 24 - (2.40 + 6 + 9 + 4.80)
= 24 - 22.2
= 1.8
1.8 pints of water will be left over.
The slope of the line is 2/1 and the y-intercept is (0,-3). Using that information, we can figure out two points on the line.
Point 1: (0,-3)
Point 2: (1,-1)
<u><em>Answer:</em></u>
Area of rhombus = 126 m²
<u><em>Explanation:</em></u>
<u>We are given that the two diagonals of the rhombus are:</u>
D₁ = 14 meters and D₂ = 18 meters
<u>The area of the rhombus using its diagonals can be calculated using the following rule:</u>

<u>Substitute with the given values to get the area as follows:</u>

Hope this helps :)