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lara31 [8.8K]
4 years ago
9

How many halves are in 3 5/10 in a diagram

Mathematics
1 answer:
lesya692 [45]4 years ago
8 0
I'm pretty sure 7 because 3 5/10 is 3 1/2 and if you make 3.5 circles it will get you 7 halves
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Which expression can be used to find the length of AT?
irina [24]

Answer:

      \large\boxed{\large\boxed{\overline{AT}=12.5(cos66\º)}}

Explanation:

In a right triangle the angle between the hypotenuse and the adjacent leg to the angle are related by the trigonometric ratio cosine.

Cosine is the ratio of the adjacent leg to the hypotenuse:

In the right triangle ART, AT is the hypotenuse,  AR is the ajacent leg to the angle 66º, and RT is the opposite leg to the angle 66º.

Then, the length of AT and 12.5 is related by the cosine ratio:

       cos(66\º)=\dfrac{\overline{AT}}{12.5}

Multiplying both sides of the equation by 12.5in:

            \overline{AT}=12.5(cos66\º)     ← answer

7 0
4 years ago
Compound Interest: You deposit $100 in an account that earns 3% annual interest compounded continuously. How long does it take t
monitta

9514 1404 393

Answer:

  a) 3.18 years

  b) 13.52 years

  c) 23.10 years

Step-by-step explanation:

Solving for t, we find ...

  A = Pe^(rt)

  A/P = e^(rt)

  ln(A/P) = rt

  t = ln(A/P)/r

For P=100 and r=.03, the times are ...

a. $110: t = ln(110/100)/.03 ≈ 3.18 years

b. $150: t = ln(150/100)/.03 ≈ 13.52 years

c. $200: t = ln(200/100)/.03 ≈ 23.10 years

6 0
3 years ago
Only question 5 pls fast
Karolina [17]

Answer:

I believe it might be 18 meters and 75 cm

Step-by-step explanation:

  1. 12m 50 cm = 1250 cm
  2. the red one is 3/5 of the green so (1250÷5)×3 = 750cm (the red ribbon)
  3. 2 \times \frac{1}{2}  =  \frac{5}{2}
  4. 750 \times  \frac{5}{2}  = 1875cm
  5. 1875cm = 18m 75cm
<h2>Hope it helps :) </h2>

sorry if it was wrong :(

7 0
3 years ago
If an object is shot with an initial velocity of 160 ft/sec, what is the smallest initial angle will you need to obtain a horizo
MrRissso [65]
To solve the question we shall use the formula for the range given by:
Horizontal range, R=[v²sin 2θ]/g
plugging in our values we get:
500=[160²×sin 2θ]/10
5000=160²×sin 2θ
0.1953=sin 2θ
thus:
arcsin 0.1953=2θ
11.263=2θ
hence:
θ=5.6315°~5.63
3 0
4 years ago
Estimate the project of 7.8 and 11.4 by rounding
ozzi
The estimate is 10 times 11 it equals 110
4 0
4 years ago
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