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Ghella [55]
3 years ago
6

Solve the given triangles by finding the missing angle and other sides lengths.

Mathematics
1 answer:
olga_2 [115]3 years ago
5 0

Answer:

75+48+x=180

x=180-123

=57degree

side length=3+3+3=9

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Which table of values will generate this graph?
lesantik [10]

Answer:

2000, x37466

Step-by-step explanation:

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1.Estimate.First round to the nearest whole number(show ur work)
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The answer to the question

7 0
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Please help me. The original blueprint of the Moreno’s’ living room has a scale of 2 inches= 5 feet. The family wants to use a n
Svetradugi [14.3K]

Answer:

Part a) The scale of the new blueprint is \frac{5}{8} \frac{in}{ft}    

Part b) The width of the living room in the new blueprint is 9.4\ in

Step-by-step explanation:

we know that

The scale of the original blueprint is

\frac{2}{5}\frac{in}{ft}

and

the width of the living room on the original blueprint is 6 inches

so

<em>Find the actual width of the living room, using proportion</em>

\frac{2}{5}\frac{in}{ft}=\frac{6}{x}\frac{in}{ft}\\ \\x=5*6/2\\ \\x=15\ ft

<em>Find the actual length of the living room, using proportion</em>

\frac{2}{5}\frac{in}{ft}=\frac{9.6}{x}\frac{in}{ft}\\ \\x=5*9.6/2\\ \\x=24\ ft

<em>Find the scale of the new blueprint</em>, divide the length of the living room on the new blueprint by the actual length of the living room

\frac{15}{24} \frac{in}{ft}

simplify  

\frac{5}{8} \frac{in}{ft}      

<em>Find the width of the living room in the new blueprint, using proportion</em>

\frac{5}{8}\frac{in}{ft}=\frac{x}{15}\frac{in}{ft}\\ \\x=15*5/8\\ \\x=9.4\ in

3 0
4 years ago
Find the equation of a line with the given points. (Put your answers in the form y = mx + b.) (7, 3) (3, 7)
igor_vitrenko [27]
By "inspection" you can write the equation as
.. x + y = 10
Then
.. y = -x +10 . . . . . . . . the desired form

8 0
3 years ago
A thermometer is taken from a room where the temperature is 24oc to the outdoors, where the temperature is −15oc. After one minu
kap26 [50]

Solution:

Use Newton's Law of Cooling.  


T = T_s + (T_0 - T_s)*e^(-kt)  


where  

T = temperature at any instant  

T_s = temperature of surroundings  

T_0 = original temperature  

t = elapsed time  

k = constant  


Now, we need to find this constant. We are given that after one hour, the temperature drops to 13° C in a 7°C Environment.  

T = 14, T_0 = 24, T_s = -15, t = 1, k = ?  

T = T_s + (T_0 - T_s)*e^(-kt)  

==> 14 = -15 + (24 - 7)*e^(-k)  

==> 14 = 7 + 17*e^(-k)  

==> 7 = 17*e^(-k)  

==> 7/13 = e^(-k)  

==> -k = ln(7/17)  

==> k = -ln(7/17) ≈ 0.774  

Now,


Let's calculate temperatures!  

T = ?, T_0 = 24, T_s = -15, k = 0.773, t = 3  

T = T_s + (T_0 - T_s)*e^(-kt)  

==> T = -15 + (24 –(-15))*e^[ -(0.774)(2) ]  

==> T = -15 + 39*e^(-1.548)  

==> T ≈ 15.72° C  

This the required answer.


7 0
3 years ago
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