Answer:
The answer is a 20% discount.
Answer:
Population in 2100 is 17.99 billion.
Step-by-step explanation:
The population of the world in 2020 = 7.8 billion.
The growth rate = 1.05%
Now find the population after 2100. Use the below formula to find the population.
Population in 2100 = Population of 2020 (1 + growth rate)^n
Population in 2100 = 7.8 (1 + 0.0105)^80
Population in 2100 = 17.99 billions.
Now, find the growth rate in 2100.
dN/dt = [r N (K – N) ] / K
r = Malthusian parameter
K = carrying capacity.
Now divide both sides by K, now x = N/K then do the differential equation.
dx/dt = r x ( 1- x)
Now integrate, x(t) = 1/ [ 1 + (1/x – 1) c^-rt
From the first equation = dN/dt = (13 – 7.8) / 80 = (r × 7.8×(13 – 7.8) / 12
0.065 = (r × 7.8× 5.2) / 12
0.065 = r × 3.38
r = 1.92%
Answer:
B
Step-by-step explanation:
This is a chemistry problem btw. But, either way, the formula for density is mass per unit of volume. To solve for volume, bring the D over to get M/D = V
(327g)/(1.05g/ml) is the equation. Grams cancel and you’re stuck with 311.428571mL. That isn’t your answer tho, because that isn’t the right amount of sig figs. We have two figs at the least so the right answer would be 311.42 or 311.43mL. We want it in scientific notation, so move the decimal place between 3 and 1. That’s two spots to the left, so the power would be 2. C is your right answer
My chem professor told me to round to even instead of rounding up all the time. Either way, the hundreds place is always a percent error of plus or minus 0.01
Answer:
6
Step-by-step explanation:
