Question

B(1)= -12

Answer 1

Given:

$b(1)=-12$

$b(n)=b(n-1)\cdot 4$

To find:

The third term of the sequence.

Solution:

We have,

$b(n)=b(n-1)\cdot 4$

For n=2, we get

$b(2)=b(2-1)\cdot 4$

$b(2)=b(1)\cdot 4$

$b(2)=-12\cdot 4$              $[\because b(1)=-12]$

$b(2)=-48$

For n=3, we get

$b(3)=b(3-1)\cdot 4$

$b(3)=b(2)\cdot 4$

$b(3)=-48\cdot 4$              $[\because b(2)=-48]$

$b(3)=-192$

Therefore, the 3rd term of the sequence is -192.