Solve for y: 4-(y-5)-(y+3)=2<br> A.25\2 <br> B.-5<br> C.2<br> D.19\5

Akimi4 [234]

Perimeter of rectangle = all sides added
= 3+3+7+7 =20

volume of sphere = 4/3 x π x r(cubed)
= 4/3 x π X 4(cubed)
= 268.08257

area of triangle = base x height / 2
= 5 x 6 / 2
=30/2 =15

volume of pyramid = base height x base width x height / 3
= 300

side of triangle ---> use Pythagoras theorem so a(squared) + b (squared) = c(squared)
4(squared) + 3(squared) = c(squared)
16 + 9 = c(squared)
25 = c(squared)
c = 5

yw sis xoxoxo

7 0

3 years ago

The diagram shows the back fences of three houses in a small neighborhood. The lengths of the fences are given.

Makovka662 [10]

Answer:

They are a Pythagorean triple that forms a right triangle

Step-by-step explanation:

a2 + b2 = c2

(5)^2 + (12)^2 = (13)^2

25 + 144 = 169

(13)^2 = 169

6 0

3 years ago

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Find the upper 20%of the weight?

meriva

Answer:

The upper 20% of the weighs are weights of at least X, which is $X = 0.84\sigma + \mu$ , in which $\sigma$ is the standard deviation of all weights and $\mu$ is the mean.

Step-by-step explanation:

Normal Probability Distribution:

Problems of normal distributions can be solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the z-score of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

Upper 20% of weights:

The upper 20% of the weighs are weighs of at least X, which is found when Z has a p-value of 0.8. So X when Z = 0.84. Then

$Z = \frac{X - \mu}{\sigma}$

$0.84 = \frac{X - \mu}{\sigma}$

$X = 0.84\sigma + \mu$

The upper 20% of the weighs are weights of at least X, which is $X = 0.84\sigma + \mu$ , in which $\sigma$ is the standard deviation of all weights and $\mu$ is the mean.

6 0

3 years ago

Several friends each had 2/5 of a bag of peanuts left over from the baseball game. They relized that they could have bought 2 fe

rosijanka [135]

5 friends went to the game because 2 divided by two fifths is five.

7 0

4 years ago

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Find the average rate of change for f(x)=9x^2+3 over the interval [x,x+h].

butalik [34]

Answer:

$9h +18x$

Step-by-step explanation:

$\frac{f(x +h) -f(x)}{x+h -x} \\ \frac{9(x +h)^2 +3 -(9x^2 +3)}{h} \\ \frac{9(x^2 +2xh +h^2) +3 -9x^2 -3 }{h} \\ \frac{9x^2 +18xh +9h^2 +3 -9x^2 -3}{h} \\ \frac{9h^2 +18xh}{h} \\ 9h +18x$

4 0

3 years ago

Solve for y: 4-(y-5)-(y+3)=2 A.25\2 B.-5 C.2 D.19\5