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malfutka [58]
3 years ago
15

Solve for y: 4-(y-5)-(y+3)=2 A.25\2 B.-5 C.2 D.19\5

Mathematics
1 answer:
Dafna11 [192]3 years ago
3 0

Answer: My answer would be 2

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a water balloon is tossed into the air with an upward velocity of 25 ft/s its height h(t) in ft after t seconds is given by the
Montano1993 [528]
When the height is 0 that is when it hits the ground
solve
0=-16t²+25x+3
cant factor so use quadratic formula

for
0=ax²+bx+c
x=\frac{-b+/-\sqrt{b^2-4ac}}{2a}

so for
0=-16t²+25t+3
a=-16
b=25
c=3
so

x=\frac{-25+/-\sqrt{25^2-4(-16)(3)}}{2(-16)}
x=\frac{-25+/-\frac{625+192}}{-32}
x=\frac{-25+/-\frac{817}}{-32}
it has to be a positive time

so it will hit the ground after \frac{25+\sqrt{817}}{32} seconds
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3 years ago
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3 years ago
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