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Arturiano [62]
3 years ago
8

Use algebraic rules of equations to predict the solution to the system of equations. Include all of your work for full credit.

Mathematics
2 answers:
dolphi86 [110]3 years ago
4 0
X+2y=10
x=10-2y

6y=-3(10-2y)+30
6y=-30+6y+30
0=0
kompoz [17]3 years ago
3 0

Answer:

infinite solutions

Step-by-step explanation:

x+2y=10

6y=-3x+30

To solve for x  and y we use substitution method

LEts solve the first equation for x

x+2y=10

Subtract 2y on both sides

x=10-2y

Now plug in x in second equation

6y=-3x+30

6y=-3(10-2y)+30

6y=-30+6y+30

6y=6y

Both sides are same , so both x  and y have infinite solutions.

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The function g(x) = 3x + x is an odd function. Which transformations of g(x) would result in odd functions? Check all
Aleksandr-060686 [28]

Answer:

-g(x),g(2x),g(-x)

Step-by-step explanation:

3 0
4 years ago
In a class, there are 15 students. 8 of them like playing soccer, 6 of them like swimming, and 2 like both and swimming and play
Katena32 [7]
I think 3
There are 15 students
-8 like soccer
-6 like swimming
-2 like both
Well if there are 8 that like soccer and 6 that like swimming and 2 like both subtract 2 from the six because they like both they are counted twice
Add 8+4=12
15-12=3
So I think 3 out of the 15 kids don’t like either
3 0
4 years ago
There are 2,100 bacteria in a circular petri dish. The dish has a radius of 40 millimeters. What is the approximate population d
Alexxx [7]
A petri dish is simply a circle; thus, we use the formula of the area of the circle which is <span>πr^2. 
Given r = 40 mm
A = </span>π(40)^2 = <span>5026.55 sq. mm
</span>
Population density = bacteria count / area
PD = 2,100 / <span>5026.55
PD = </span><span>0.417782 bacteria / mm sq.

Therefore, the answer is approximately 0.418 </span><span>bacteria per square millimeter.</span>
8 0
4 years ago
Read 2 more answers
Please help me right away with these problems.
viktelen [127]

Q.34

\sum\limits_{k=1}^{\infty}420\left(1.002\right)^{k-1}

The infinite geometric series is converges if |r| < 1.

We have r =1.002 > 1, therefore our infinite geometric series is Diverges

Answer: c. Diverges, sum not exist.

Q.35

\sum\limits_{k=1}^{\infty}-5\left(\dfrac{4}{5}\right)^{k-1}

The infinite geometric series is converges if |r| < 1.

We have r = 4/5 < 1, therefore our infinite geometric series is converges.

The sum S of an infinite geometric series with |r| < 1 is given by the formula :

S=\dfrac{a_1}{1-r}

We have:

a_1=-5\left(\dfrac{4}{5}\right)^{1-1}=-5\left(\dfrac{4}{5}\right)^0=-5\\\\r=\dfrac{4}{5}

substitute:

S=\dfrac{-5}{1-\frac{4}{5}}=-\dfrac{5}{\frac{1}{5}}=-5\cdot\dfrac{5}{1}=-25

Answer: c. Converges, -25.

4 0
3 years ago
Write an expression that can be usedto find the nth termo of each sequence 9, 17, 25, 33
ra1l [238]

Answer:

The expression used to find the nth term of each sequence 9, 17, 25, 33 will be:

  • a_n=8n+1

Step-by-step explanation:

Given the sequence

9, 17, 25, 33

a₁ = 9

<em>Determining the common difference</em>

d = 17-9 = 8

d = 25-17 = 8

d = 33-25 = 8

As the common difference between the adjacent terms is same and equal to

d = 8

Therefore, the given sequence is an Arithmetic sequence.

An arithmetic sequence has a constant difference 'd' and is defined by  

a_n=a_1+\left(n-1\right)d

substituting a₁ = 9, d = 8 in the equation

\:a_n=9+8n-8

a_n=8n+1

Therefore, the expression used to find the nth term of each sequence 9, 17, 25, 33 will be:

  • a_n=8n+1
6 0
3 years ago
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