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prisoha [69]
3 years ago
13

Please help me right away with these problems.

Mathematics
1 answer:
viktelen [127]3 years ago
4 0

Q.34

\sum\limits_{k=1}^{\infty}420\left(1.002\right)^{k-1}

The infinite geometric series is converges if |r| < 1.

We have r =1.002 > 1, therefore our infinite geometric series is Diverges

Answer: c. Diverges, sum not exist.

Q.35

\sum\limits_{k=1}^{\infty}-5\left(\dfrac{4}{5}\right)^{k-1}

The infinite geometric series is converges if |r| < 1.

We have r = 4/5 < 1, therefore our infinite geometric series is converges.

The sum S of an infinite geometric series with |r| < 1 is given by the formula :

S=\dfrac{a_1}{1-r}

We have:

a_1=-5\left(\dfrac{4}{5}\right)^{1-1}=-5\left(\dfrac{4}{5}\right)^0=-5\\\\r=\dfrac{4}{5}

substitute:

S=\dfrac{-5}{1-\frac{4}{5}}=-\dfrac{5}{\frac{1}{5}}=-5\cdot\dfrac{5}{1}=-25

Answer: c. Converges, -25.

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Question 7 of 10 What is the slope of the line shown below? A. 2 B.-2 C.4 D.-4​
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Read 2 more answers
Show the following numbers on number line 3/2, 5/2, -3/2
pav-90 [236]

When you create the number line, put 0 in the middle. Basically you put all the numbers you got from least to greatest on the number.

Since -3/2 is less than 0, it will go to the left of 0.

Since 3/2 and 5/2 are greater than 0, it will go to the right of 0.

Remember to use sub points of 1.

Best of Luck!

3 0
3 years ago
HELP ME PLEASEEEEEEEEE
Nataliya [291]

Answer:

a)This solution matches with the original equation and its solution

b)This solution matches with the original equation and its solution

c)This solution <em><u>does not</u></em> match with the original equation and its solution. Though the solution is correct the original given equation cannot be used.

d)This solution <em><u>does not</u></em> match with the original equation and its solution. Though the solution is correct the original given equation cannot be used.

Step-by-step explanation:

i) Which scenarios can be solved by 1.5x +  2.25 = 12.75. Select all that apply and note the given solution.

therefore 1.5x = 10.5   therefore x  = 7

a) let the number be x

   therefore if \frac{3}{2} x + \frac{9}{4}  = \frac{51}{4}  \Rightarrow  1.5x + 2.25 = 12.75  then the number x = 7.

 This solution matches with the original equation and its solution

b.) If a taxi driver charges a flat fee of $2.25 and $1.5 per mile, where the

     number of mile = x, then the number of miles Juan can ride the taxi for

     $12.75 is x = 7.

This solution matches with the original equation and its solution

c)if nine quarters of a number, say x, increased by three halves is fifty one

   quarters, the number is x = 5,

   \frac{9}{4} x + \frac{3}{2}  = \frac{51}{4}  \Rightarrow  9x = 51 - 6 = 45 \therefore x = 5

This solution <em><u>does not</u></em> match with the original equation and its solution. Though the solution is correct the original given equation cannot be used.

d.)   If a taxi driver charges a flat fee of $1.5 and $2.25 per mile, where the

     number of mile = x, then the number of miles Juan can ride the taxi for

     $12.75 is x = 5.

2.25x + 1.5  = 12.75  \Rightarrow  9x = 51 - 6 = 45 \therefore x = 5

This solution <em><u>does not</u></em> match with the original equation and its solution. Though the solution is correct the original given equation cannot be used.

3 0
3 years ago
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