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Klio2033 [76]
2 years ago
14

Pi times 54 -78 you cant simplify

Mathematics
1 answer:
AnnyKZ [126]2 years ago
8 0

Answer :91.646

Step-by-step explanation:

sorry if worg

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If we have two similar triangles:
Triangle 1 (base 1 , height1).
Triangle 2 (base 2, height 2)
Then:

base 1 /height 1=base 2 /height 2

Data:
base 1=0.2 m
height 1= 1 m
base 2= 8 m
height 2=x

We calculate the height of the tower:
base 1 /height 1=base 2 /height 2
0.2 m / 1m=8 m / x
x=(8 m * 1 m) / 0.2 m
x=8 m²/0.2 m
x=40 m

Answer. the heigth of the tower will 40 m

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3 years ago
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Determine the missing number in the equation 13-2=12-?​
soldier1979 [14.2K]

For the equation to work, you have to have the same number on both sides of the equal sign

so to find ?, you can do:

13 - 2 = 12 - ?       Simplify

11 = 12 - ?       Subtract 12 on both sides

-1 = - ?     Multiply -1 on both sides

1 = ?

5 0
3 years ago
Find dy/dx by implicit differentiation.
kow [346]

dy/dx by implicit differentiation is cos(πx)/sin(πy)

<h3>How to find dy/dx by implicit differentiation?</h3>

Since we have the equation

(sin(πx) + cos(πy)⁸ = 17, to find dy/dx, we differentiate implicitly.

So, [(sin(πx) + cos(πy)⁸ = 17]

d[(sin(πx) + cos(πy)⁸]/dx = d17/dx

d[(sin(πx) + cos(πy)⁸]/dx = 0

Let sin(πx) + cos(πy) = u

So, du⁸/dx = 0

du⁸/du × du/dx = 0

Since,

  • du⁸/du = 8u⁷ and
  • du/dx = d[sin(πx) + cos(πy)]/dx

= dsin(πx)/dx + dcos(πy)/dx

= dsin(πx)/dx + (dcos(πy)/dy × dy/dx)

= πcos(πx) - πsin(πy) × dy/dx

So, du⁸/dx = 0

du⁸/du × du/dx = 0

8u⁷ × [ πcos(πx) - πsin(πy) × dy/dx] = 0

8[(sin(πx) + cos(πy)]⁷ ×  (πcos(πx) - πsin(πy) × dy/dx) = 0

Since 8[(sin(πx) + cos(πy)]⁷ ≠ 0

(πcos(πx) - πsin(πy) × dy/dx) = 0

πcos(πx) = πsin(πy) × dy/dx

dy/dx = πcos(πx)/πsin(πy)

dy/dx = cos(πx)/sin(πy)

So, dy/dx by implicit differentiation is cos(πx)/sin(πy)

Learn more about implicit differentiation here:

brainly.com/question/25081524

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6 0
1 year ago
On Tuesday the temperature is 1 ºC. By Wednesday it has dropped to –2 ºC. The temperature drops by twice as much from Wednesday
Finger [1]

Answer: -8^{\circ}C

Step-by-step explanation:

Given

The temperature on Tuesday is 1^{\circ}C

Temperature drops to -2^{\circ}C on Wednesday

Net drop in temperature 1-(-2)=3^{\circ}C

The temperature drops twice from Wednesday to Thursday

\Delta T=2\times 3=6^{\circ}C

Temperature on Thursday

\Rightarrow -2-6=-8^{\circ}C

3 0
2 years ago
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