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3 years ago

Pi times 54 -78 you cant simplify

Mathematics

1 answer:

AnnyKZ [126]3 years ago

8 0

Answer :91.646

Step-by-step explanation:

sorry if worg

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Can someone please help me

fenix001 [56]

It’s the bottom right

8 0

3 years ago

x P(x) 0 0.25 1 0.3 2 0.1 3 0.35 Find the standard deviation of this probability distribution. Give your answer to at least 2 de

barxatty [35]

Answer:

The standard deviation of this probability distribution is 1.2.

Step-by-step explanation:

We have that:

P(X = 0) = 0.25

P(X = 1) = 0.3

P(X = 2) = 0.1

P(X = 3) = 0.35

Mean:

Each value multiplied by its probability. So

$M = 0*0.25 + 1*0.3 + 2*0.1 + 3*0.35 = 1.55$

Variance:

Sum of the squares of the values subtracted from the mean, and multiplied by its probability.

$V = 0.25*(0-1.55)^2 + 0.3*(1-1.55)^2 + 0.1*(2-1.55)^2 + 0.35*(3-1.55)^2 = 1.4475$

Standard deviation:

Square root of the variance. So

$S = \sqrt{V} = \sqrt{1.4475} = 1.2$

The standard deviation of this probability distribution is 1.2.

6 0

3 years ago

PLEASE HELP MEE!!! please only answer if you really know the answer.

Komok [63]

Answer:

They are similar.

Step-by-step explanation:

Triangle VLM is only 3.5 times smaller than UTM

3 0

3 years ago

lyudmila [28]

${\large{\textsf{\textbf{\underline{\underline{Given :}}}}}}$

★ ∆ ABC is similar to ∆DEF

★ Area of triangle ABC = 64cm²

★ Area of triangle DEF = 121cm²

★ Side EF = 15.4 cm

${\large{\textsf{\textbf{\underline{\underline{To \: Find :}}}}}}$

★ Side BC

${\large{\textsf{\textbf{\underline{\underline{Solution :}}}}}}$

Since, ∆ ABC is similar to ∆DEF

[ Whenever two traingles are similar, the ratio of the areas of two similar triangles is equal to the square of the ratio of their corresponding sides. ]

$\therefore \tt \boxed{ \tt \dfrac{area( \triangle \: ABC )}{area( \triangle \: DEF)} = { \bigg(\frac{BC}{EF} \bigg)}^{2} }$

❍ Putting the values, [Given by the question]

• Area of triangle ABC = 64cm²

• Area of triangle DEF = 121cm²

• Side EF = 15.4 cm

$\implies \tt \dfrac{64 \: {cm}^{2} }{12 \: {cm}^{2} } = { \bigg( \dfrac{BC}{15.4 \: cm} \bigg) }^{2}$

❍ By solving we get,

$\implies \tt \sqrt{\dfrac{{64 \: cm}^{2} }{ 121 \: {cm}^{2} }} = \bigg( \dfrac{BC}{15.4 \: cm} \bigg)$

$\implies \tt \sqrt{\dfrac{{(8 \: cm)}^{2} }{ {(11 \: cm)}^{2} }} = \bigg( \dfrac{BC}{15.4 \: cm} \bigg)$

$\implies \tt \dfrac{8 \: cm}{11 \: cm} = \dfrac{BC}{15.4 \: cm}$

$\implies \tt \dfrac{8 \: cm \times 15.4 \: cm}{11 \: cm} = BC$

$\implies \tt \dfrac{123.2 }{11 } cm = BC$

$\implies \tt \purple{ 11.2 \: cm} = BC$

Hence, BC = 11.2 cm.

${\large{\textsf{\textbf{\underline{\underline{Note :}}}}}}$

★ Figure in attachment.

$\rule{280pt}{2pt}$

4 0

2 years ago

Please, show me how to find the limit. lim θ sin θ θ→π Thank you!

Morgarella [4.7K]

Ignore the fact that it says limit because when sin (pi) is here it is not an Undefined Point, whatever value the calculator says is sin(pi) is the answer.

5 0

3 years ago