log (m + n) = log m+ log n and proved it m =n/n-1
Given;
If log (m + n) = log m+ log n
To show that the m =n/n-1
Now, According to the question:
We know that,
Log (m + n) = log m + log n
Log (m + n ) = log (mn). [log a + log b = log ab ]
Cancelling the log on both sides.
then,
m + n = mn
=> n = mn - m
=> n = m (n - 1)
=> m = n / n - 1
Hence Proved
log (m + n) = log m+ log n and proved it m =n/n-1
What is Logarithm?
A logarithm is the power to which a number must be raised in order to get some other number (see Section 3 of this Math Review for more about exponents). For example, the base ten logarithm of 100 is 2, because ten raised to the power of two is 100: log 100 = 2.
Learn more about Logarithm at:
brainly.com/question/16845433
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Answer: OPTION C.
Step-by-step explanation:
1. To solve this problem you must apply the Pythagorean Theorem, which is shown below:

Where a is the hypotenuse, and b and c are the legs of the triangle.
2. When you solve for one of the legs and substitute values, you obtain that the result is:

This is possible providing the garden is in the shape that has equal sides, such as a square or an equilateral triangle.
Area of a square is found by multiplying one side to the other, which would be the same as multiplying two same numbers.
It's 8! range is just the greatest value minus the lowest value
(=^_^=)