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2 years ago

Hey besties there's another topic i need help with anyways here it is

Mathematics

1 answer:

Tatiana [17]2 years ago

8 0

Answer:

21/2.5= 8.4

3.5(8.4)= 29.4 scoops

(i hope this is correct)

Step-by-step explanation:

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Solve.<br><br> 5x-2y<10<br> I give Brainliest!

Anestetic [448]

<h2>Answer:</h2>

This is impossible to solve.

<h2>Step-by-step explanation:</h2>

For an equation or inequality to be solvable, there must be the same number of inequalities as variables. Here, there is an x and there is a y. This means that you need at least two inequalities to solve it.

You can, however, rearrange to get x or y on one side.

This can be done for x:

5x < 10 + 2y

x < 2 + 2/5y

Or it can be done for y:

5x < 10 + 2y

5x - 10 < 2y

2.5x - 5 < y

8 0

2 years ago

Dont guess!<br> I will mark brainliest if its correct!<br> Also no links!

brilliants [131]

Answer:

I know you said no guessing, but I'm assuming it's the first one, F.

8 0

2 years ago

Read 2 more answers

What is the equivalent ratio of 9:3 ?

Stells [14]

3:1 should be the answer.

7 0

2 years ago

Read 2 more answers

Does the following table show a proportional relationship between the variables x and y? x 5/6 25/6 125/6 y 2 10 50

ki77a [65]

Answer: A:Yes

Step-by-step explanation:

This table shows a proportional relationship between the variables x and y.

3 0

2 years ago

Can someone please help me with my maths question

DIA [1.3K]

Answer:

$a. \ \dfrac{625 \cdot m}{27 \cdot n^{11}}$

$b. \ \dfrac{x^{3 \cdot m - 2}}{y^{ 3 + n}}$

Step-by-step explanation:

The question relates with rules of indices

(a) The give expression is presented as follows;

$\dfrac{m^3 \times \left (n^{-2} \right )^4 \times (5 \cdot m)^4}{\left (3 \cdot m^2 \cdot n \right )^3}$

By expanding the expression, we get;

$\dfrac{m^3 \times n^{-8} \times 5^4 \times m^4}{\left 3^3 \times m^6 \times n^3}$

Collecting like terms gives;

$\dfrac{m^{(3 + 4 - 6)} \times 5^4}{ 3^3 \times n^{3 + 8}} = \dfrac{625 \cdot m}{27 \cdot n^{11}}$

$\dfrac{m^3 \times \left (n^{-2} \right )^4 \times (5 \cdot m)^4}{\left (3 \cdot m^2 \cdot n \right )^3}= \dfrac{625 \cdot m}{27 \cdot n^{11}}$

(b) The given expression is presented as follows;

$x^{3 \cdot m + 2} \times \left (y^{n - 1} \right )^3 \div (x \cdot y^n)^4$

Therefore, we get;

$x^{3 \cdot m + 2} \times \left (y^{n - 1} \right )^3 \times x^{-4} \times y^{-4 \cdot n}$

Collecting like terms gives;

$x^{3 \cdot m + 2 - 4} \times \left (y^{3 \cdot n - 3 -4 \cdot n}} \right ) = x^{3 \cdot m - 2} \times \left (y^{ - 3 -n}} \right ) = x^{3 \cdot m - 2} \div \left (y^{ 3 + n}} \right )$

$x^{3 \cdot m - 2} \div \left (y^{ 3 + n}} \right ) = \dfrac{x^{3 \cdot m - 2}}{y^{ 3 + n}}$

$x^{3 \cdot m + 2} \times \left (y^{n - 1} \right )^3 \times x^{-4} \times y^{-4 \cdot n} =\dfrac{x^{3 \cdot m - 2}}{y^{ 3 + n}}$

4 0

3 years ago