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Rudiy27
3 years ago
14

What is the answer for 4=0.5z-4

Mathematics
2 answers:
amm18123 years ago
7 0
Answer is 16

4=0.5z-4
4+4=0.5z
8=0.5z
z=16

I isolated Z
padilas [110]3 years ago
5 0
8 = 0.5 z
8/ 0.5 = z
z = 16
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OLEGan [10]
43.
The coefficient of something is the numerical value in that term. For example, if we have 4x. The coefficient is 4.
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Multiply each equation by a constant that would help to eliminate the y terms.
Zinaida [17]

Answer:

Therefore the required resulting equation is

6x-15y=-63\\-15x+15y=90

6 x minus 15 y = negative 63.

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Step-by-step explanation:

Given:

2x-5y=-21         ......................Equation ( 1 )

3x-3y=-18         ......................Equation ( 2 )

To Find:

Expression after multiplying to eliminate y term,

Solution:

So to eliminate 'y' term we need to multiply equation 1 by a constant 3 and equation 2 by a constant -5,  such that equations  becomes

3(2x-5y)=3\times -21\\\\6x-15y=-63 .....( 1 )

-5(3x-3y)=-5\times -18\\\\-15x+15y=90  .....( 2 )

so now by adding new equation one and two we can eliminate y term that means -15y and +15y will get cancel,

Therefore the required resulting equation is

6x-15y=-63\\-15x+15y=90

6 x minus 15 y = negative 63.

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3 years ago
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Researchers fed mice a specific amount of Toxaphene, a poisonous pesticide, and studied their nervous systems to find out why To
Mkey [24]

Answer:

a. The mean refractory period= 1.85 and the standard error = 0.06455

b.  90% confidence interval for the mean absolute refractory period for all mice when subjected to the same treatment = 1.6981, 2.0019

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Step-by-step explanation:

a.  The table below shows the calculations:

                 X                (X-mean)^2

                1.7             0.0225

                1.8                 0.0025

                1.9                 0.0025

                2.0                 0.0225

Total        7.4                  0.05

Sample size: n=4

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The sample standard deviation, s = \sqrt{\frac{\sum \left ( x-\bar{x} \right )^{2}}{n-1}}=0.1291

The standard error, se= \frac{s}{\sqrt{n}}=\frac{0.1291}{2} = 0.06455

b. Degree of freedom: df = n-1 = 3

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H_{0}:\mu=1.3,H_{1}:\mu>1.3

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t=\frac{\bar{x}-\mu}{s/\sqrt{n}}=8.52

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Answer:

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Step-by-step explanation:

i hope it would help u

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Step-by-step explanation:

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